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Art [367]
2 years ago
10

three molecules of oxygen react with four molecules of hydrogen to produce water molecules write a balanced chemical equation

Chemistry
1 answer:
mixer [17]2 years ago
6 0

Answer:

ExpC

H

4

+  

2

O

2

 

→

 

C

O

2

+  

2

H

2

O

This is the balanced reaction equation for the combustion of methane.

Explanation:

The Law of Conservation of Mass basically states that matter can neither be created nor destroyed. As such, we must be able to show this in our chemical reaction equations.

If you look at the equation above, you'll see an arrow that separates the reaction equation into two parts. This represents the direction of the reaction.

To the left of the arrow, we have our reactants.

To the right of the arrow, we have our products.

The quantity of each individual element in the left must equal the quantity of each individual element in the right.

So if you look below, you'll see the unbalanced equation, and I'll try to explain how to balance the reaction.

C

H

4

+  

O

2

 

→

 

C

O

2

+  

H

2

O

Our reactants in this equation are  

C

H

4

and  

O

2

.

Our next step is to break these down into individual atoms.

We have:

1 C atom, 4 H atoms & 2 O atoms.

If you're confused by this, look to see the little number to the bottom right of each element, the subscript, and it tells you how many of each atom are in the molecule. Make sense?

Now we look to the other side of the equation.

Here we see our products are  

C

O

2

+  

H

2

O

Again, we break these down into individual atoms again.

We have:

1 C atom, 2 H atom, 3 O atom

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Nataly [62]
Yes, because CO2 is carbon dioxide, and carbon dioxide contains molecules.
5 0
2 years ago
I don't know how to do this can I get the answers plz it's due in 1 hour
katrin [286]
Okay, so even if I just gave you the answers, your teacher needs work on it too so it'll be easier/better if I just explain how to do it.
Basically, both sides need to have the same number of molecules. To do this, we make charts. This is the first side of number one:
Na - 1
Mg- 1
F - 2
The subscript gives F two molecules, and the other ones only each have one. This is the second side:
Na- 1
Mg- 1
F- 1
So they're not equal. To fix this, we add coefficients. These are numbers that are going to appear in the front of each compound/element and changes the number of molecules of the WHOLE compound/element. We need two F on the second side, so we'll put a coefficient of 2 in front of NaF. The new chart for the second side is this:
Na- 2
Mg- 1
F- 2
Now we've fixed the F, but now Na is off! So let's go to the first side again and see what we can do. We can put a 2 in front of the Na. The new chart is this:
Na- 2
Mg -1
F- 2
Now both sides are the same. The full new equation is:
2Na + MgF(sub2) = 2NaF + Mg
Basically, do this for all of them. Feel free to ask more questions.
4 0
3 years ago
Read 2 more answers
Which of the following represents the velocity of a light wave?
Softa [21]

Answer:

<h3>D. c = fλ</h3>

Explanation:

c = fλ

where" c "is the speed of light ,

• "f" is the frequency of the electromagnetic waves,

• " λ" is its wavelength.

3 0
2 years ago
Select the true statements about protein secondary structure.
netineya [11]

Answer:

The α‑helix is held together by hydrogen bonds between the amide N−H and C=O groups.

Disulfide bonds stabilize secondary structure.

Explanation:

Proteins have primary, secondary, tertiary and quartinary structures.

The secondary structure of a protein is the regular, recurring sequence of amino acid in a polypeptide chain. Secondary structure of proteins give rise to the folding observed in the structure of a protein.

The major secondary structures of a protein are α-helices and β-structures.

7 0
2 years ago
Given the wavelength of the corresponding emission line, calculate the equivalent radiated energy from n = 4 to n = 2 in both jo
lions [1.4K]

Explanation:

It is given that,

Initial orbit of electrons, n_i=4

Final orbit of electrons, n_f=2

We need to find energy, wavelength and frequency of the wave.

When atom make transition from one orbit to another, the energy of wave is given by :

E=-13.6(\dfrac{1}{n_f^2}-\dfrac{1}{n_i^2})

Putting all the values we get :

E=-13.6(\dfrac{1}{(4)^2}-\dfrac{1}{(2)^2})\\\\E=2.55\ eV

We know that : 1\ eV=1.6\times 10^{-19}\ J

So,

E=2.55\times 1.6\times 10^{-19}\\\\E=4.08\times 10^{-19}\ J

Energy of wave in terms of frequency is given by :

E=hf

f=\dfrac{E}{h}\\\\f=\dfrac{4.08\times 10^{-19}}{6.63\times 10^{-34}}\\\\f=6.14\times 10^{14}\ Hz

Also, c=f\lambda

\lambda is wavelength

So,

\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{6.14\times 10^{14}}\\\\\lambda=4.88\times 10^{-7}\ m\\\\\lambda=488\ nm

Hence, this is the required solution.

4 0
3 years ago
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