Answer:
The period, T = 1.4183 seconds, and
the length of the pendulum, L = 0.5 meters
Explanation:
Formula for period T = 2π/v
Where π = 3.1416
velocity of pendulum, v = 4.43 rad/s
Therefore, T = 2 × 3.1416/4.43 = 1.4183 seconds
Formula for length of a pendulum, L = g/v²
Where g = 9.81 m/s²
v = 4.43 rad/s
Therefore, L = 9.81/4.43² = 0.5 meters.
1.
A:Time (minutes)
B: Temp(degrees c)
2. Downward trend (temperature goes down as time goes on )
3.
A: not sure
B: temperature
4.the temperature is going down
5. Closes off any open airways
1411.8 N/m
From Hooke's law;
F= Ke
Where
F= force on the spring
K= force constant
e = extension
But e= 8.50 × 10^-2m
F= weight = 12.0 kg × 10 = 120 N
K = F/e = 120/8.50 × 10^-2
K= 1411.8 N/m
98.1 Joule
Solution,
⇒Mass(m)=10kg
⇒Weight(F)=Mg=10×9.81=98.1N
⇒Distance(d)=1m
Now,
Work done=F×d
=98.1×1
=98.1J
please dont mind me just looking for points
