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lesantik [10]
3 years ago
14

From because when held inhands stmah 3.in an experiment to determine the density of Sand using a density bottle, the following m

easurements were recorded: Mass of empty of density bottle=43.2g Mass of density bottle full of water=66.4g Mass of density bottle with some sand =67.5g Mass of density bottle with sand, filled up with water=82.3g Use the above data to determine the: a) mass of the water that filled the bottle 1mks b) Volume of the water that filled the bottle. 2mk c) Volume of the density bottle Imk. d) Mass of sandlmk e) Mass of water that filled the space above the sand lmk • • • f) Volume of the sand 3mk Density of the sand​

Physics
1 answer:
BARSIC [14]3 years ago
4 0

What argument does Minow make in his speech?

A. Parents should demand better programs for their children to watch in the evenings.

B. People watch too much television, which leads to boredom and violence.

C. Television executives have a responsibility to provide better programming.

D. The nation's children depend on television to entertain and educate them.

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What is the frequency of highly energetic ul-
Mnenie [13.5K]

Frequency = (speed) / (wavelength)

Frequency = (3 x 10⁸ m/s) / (124 x 10⁻⁹ m)

Frequency = <em>2.42 x 10¹⁵ Hz</em>

8 0
3 years ago
A 1020 kg boat is traveling at 110 km/h when its engine is shut off. The magnitude of the frictional force k between boat and wa
nordsb [41]

Answer: 94 seconds

Explanation:

An exact solution will require calculus, since the acceleration is not constant.


M*dV/dt = -fk = -75V
dV/V = -(75/M)dt



Since you have separated variables to opposite sides, the differential equation is easily integrated. 



Therefore,

V2/V1 = -ln2 = (-75/M)T
where T is the time interval.



Then we have that,

T= (M/75)*ln2 = (1020/75)*0.693
= 94 seconds

4 0
3 years ago
a solid passes from point A to B by VA=2m/s. AB=1m;m=2kg;F=2N and f=0.5N.Calculate the speed at point B​
slava [35]

Answer:

a and E

Explanation:

4 0
3 years ago
A 50-gram ball is released from rest 80 m above the surface of the Earth. During the fall to the Earth, the total thermal energy
Nady [450]

Answer:

Speed of ball just before it hit the surface is 31.62 m/s .

Explanation:

Given :

Mass of ball , m = 50 g = 0.05 kg .

Height from which it falls , h = 80 m .

Thermal energy , E = 15 J .

Now , Initial energy of the system is :

E_i=\dfrac{mv^2}{2}+mgh

Here , initial velocity is zero .

Therefore , E_i=mgh=40\ J

Now , final energy of the system :

E_f=\dfrac{mv^2}{2}+mg(0)+15\\\\E_f=\dfrac{0.05\times v^2}{2}+15

Since , no external force is applied .

Therefore , total energy of the system will be constant .

By conservation of energy :

E_i=E_f\\40=\dfrac{0.05v^2}{2}+15\\\\25=\dfrac{0.05v^2}{2}\\\\v=31.62\ m/s

Therefore , speed of ball just before it hit the surface is 31.62 m/s .

3 0
3 years ago
Please help!! Also please explain if possible...
solmaris [256]

This is third equation of motion. As there is no values given, I assume you just have to keep variable 'a' (representing acceleration) on one side of the equation and all other variables on the other side.

v_{f}^{2}= v_{o}^{2}+2a(x_{f}-x_{o})

v_{f}^{2}- v_{o}^{2}=2a(x_{f}-x_{o})

\frac{v_{f}^{2}- v_{o}^{2}}{2(x_{f}-x_{o})}=a

OR

a=\frac{v_{f}^{2}- v_{o}^{2}}{2(x_{f}-x_{o})}

Here, v_{o} is initial velocity,

v_{f} is final velocity ,

x_{o} is initial position,

x_{f} is final position, and

a is acceleration.

3 0
3 years ago
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