From because when held inhands stmah 3.in an experiment to determine the density of Sand using a density bottle, the following m
easurements were recorded: Mass of empty of density bottle=43.2g Mass of density bottle full of water=66.4g Mass of density bottle with some sand =67.5g Mass of density bottle with sand, filled up with water=82.3g Use the above data to determine the: a) mass of the water that filled the bottle 1mks b) Volume of the water that filled the bottle. 2mk c) Volume of the density bottle Imk. d) Mass of sandlmk e) Mass of water that filled the space above the sand lmk • • • f) Volume of the sand 3mk Density of the sand
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Here , the density of the material is 4g cm³ but it is not given in CGS system.
$\sf{As\:we\:know\:that:}$
$\sf\bold{Density=}$ $\sf\dfrac{Mass}{Volume}$
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$\sf\small{Density\:of\:the\:material=4}$ $\sf\dfrac{g}{cm^2}$
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$\sf{It\:is\:given\:that:}$
In the system of units the mass is 100gram.
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Hence,
$\sf{The\:mass\:unit\:for\:4g=}$ $\sf\dfrac{4}{100}$ $\sf{units}$
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In the system of units,the length is 10cm.
Henceforth,
$\sf\small{The\:length \:for\:1cm\:units=}$ $\sf\dfrac{1}{10}$ $\sf{units}$
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<u>☆</u><u> </u><u>Substitute</u><u> </u><u>the</u><u> </u><u>required</u><u> </u><u>values</u><u> </u><u>in</u><u> </u><u>the</u><u> </u><u>given</u><u> </u><u>formula</u><u>-</u>
$\sf\purple{Density=}$ $\sf\dfrac\purple{Mass}\purple{volume}$
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$\sf\underline\bold{Density\:of\:the\:material:}$
= $\sf\dfrac{4/100}{1/10^3}$ $\sf\bold{units}$
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= $\sf\dfrac{4/100}{1/1000}$ $\sf\bold{units}$
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= $\sf\dfrac{4000}{100}$ $\sf\bold{units}$
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$\sf\underline\bold\blue{=40\:units}$
$\sf\small{Therefore,option\:2nd\:is\:correct!}$
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