Both D and G options. Weak base and its conjugate acid or weak acid and its conjugate base are the possible components of a buffer solution.
Explanation:
Buffer solution is the solution which gets easily dissolved in water and so called as "Aqueous solution".
Buffer solution is essentially made up of two components Known as:
i.) Weak base and its conjugate acid
ii.) Weak acid and its conjugate base
This weak acid and base solution is used to maintain the pH value of the solution in a balanced way.
When the weak acid or base solution is added to strong acid or base solution that is the way pH gets balanced .
In one word buffer solution is the solution which resists for the pH change when strong acids or bases are added.
Answer:
It is
Explanation:
The reason is because it is giving out waves of sound to create music making energy.
Molarity is defined as the number of moles of solute in 1 L of solution
the mass of Ca(NO₃)₂ present - 8.50 g
therefore number of moles of Ca(NO₃)₂ - 8.50 g / 164 g/mol = 0.0518 mol
the volume of solution prepared is 755 mL
therefore if there are 0.0518 mol in 755 mL
then in 1000 mL the number of moles - 0.0518 mol / 0.755 L
molarity is therefore - 0.0686 M
> 2,000
mL of a 5.0 × 10–5% (w/v) sucrose solution
5.0 × 10–3
g/mL * 2000 mL * (1 mol / 342.30 g) = 0.0292 mol
<span>
> 2,000 mL of a 5.0 ppm sucrose solution</span>
5 grams /
1000000 mL * 2000 mL* (1 mol / 342.30 g) = 0.0000292 mol
<span>
> 20 mL of a 5.0 M sucrose solution </span>
5.0 M *
0.020 L = 0.1 mol
Answer:
<span>2,000 mL
of a 5.0 ppm sucrose solution</span>
It means <span>a substance formed by chemical union of 2 or more elements or ingredients in definite proportion by weight.</span>
