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MAXImum [283]
3 years ago
10

Which is the balanced single displacement reaction between Aluminum (Al3+) and Copper Sulfate (Cu2+(SO4)2-)

Chemistry
1 answer:
Aliun [14]3 years ago
4 0

Answer:

The balanced single displacement reaction between aluminum and copper sulphate is as follows.

2Al(s)+3CuSO_{4}(aq)\rightarrow Al_{2}(SO_{4})_{3}(aq)+3Cu(s)

Explanation:

The given ions are as follows.

Al^{3+}- Aluminium ion and copper sulfate ion.

Single displacement reaction occurs one element replaces another element.

Hence, the balanced chemical reaction is as follows.

2Al(s)+3CuSO_{4}(aq)\rightarrow Al_{2}(SO_{4})_{3}(aq)+3Cu(s)

<u>Oxidation half reaction:</u>

Al\rightarrow Al^{3+}+3e^{-}

Aluminium loses three electrons.

<u>Reduction half reaction:</u>

<u>Cu^{2+}+2e^{-}\rightarrow Cu(s)</u>

Copper gain three electrons.

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Answer:

= 20.82 g of BaCl2

Explanation:

Given,

Volume = 200 mL

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Therefore; 0.1 mole of BaCl2 will be equivalent to;

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  = 20.82 g

Therefore, the mass of BaCl2 in grams required is 20.82 g

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2 years ago
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