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3 years ago

How does the Moon affect Earth? Describe two examples. Edmentum answer

Physics

2 answers:

Gelneren [198K]3 years ago

4 0

Answer:

Gravity

Explanation:

anzhelika [568]3 years ago

4 0

Answer:

The Moon creates tides

As Earth spins on its own axis, gravity and centrifugal force keeps ocean waters at equal levels.

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A maglev is a type of train that rides on a "cushion of magnetism." These trains can attain very high speeds because

marissa [1.9K]

Answer:

A. friction is greatly reduced.

Explanation:

Maglev train runs on the principle of repulsion force due to magnetic field

here we know that magnetic field will apply force on the train which helps to levitate train in air

This is why it runs forward due to other component of magnetic force and hence it can run with high speed in air with least friction as there is no two surfaces in contact with each other

So here we can say that

Train run with very high speed due to least value of friction between two surfaces which moves relative to each other

so correct answer is

A. friction is greatly reduced.

6 0

3 years ago

A car traveling at 30m/s slows down to a stop 10s. what is the acceleration?

Usimov [2.4K]

Answer:

20 m/s. have a great day

5 0

3 years ago

Read 2 more answers

Could someone please tell me what I'm doing wrong?

7nadin3 [17]

Answer:

M1 = 16.9 mA

M2 = 0 A

Explanation:

As the ratio of the two sets of series resistors is almost exactly identical, there is no voltage difference across M2 to cause current flow

269/(269 + 439) = 0.3799...

500/(500 + 815) = 0.38022

M2 = 0

M1 sees only the current flowing through the far left resistors in series

A = V/R = 12/(269 + 439) = 0.016949... ≈ 16.9 mA

7 0

3 years ago

An object of mass 100 kg is accelerated uniformly from a velocity of 5 ms–1

solniwko [45]

Answer:

Initial velocity of the object, u = 5 m/s

Final velocity of the object, v = 8 m/s

Mass of the object, m = 100 kg

Time take by the object to accelerate, t = 6 s

Initial momentum = mu = 100 — 5 = 500 kg m sˆ’1

Final momentum = mv = 100 — 8 = 800 kg m sˆ’1

Force exerted on the object, F = mv – mu / t

= m (v-u) / t

= 800 – 500

= 300 / 6

= 50 N

Initial momentum of the object is 500 kg m sˆ’1.

Final momentum of the object is 800 kg m sˆ’1.

Force exerted on the object is 50 N.

mark this as brainliest!

6 0

4 years ago

At time t=0t=0 a proton is a distance of 0.360 mm from a very large insulating sheet of charge and is moving parallel to the she

insens350 [35]

Answer:

$1.34 * 10^{3}$ m/s

Explanation:

Parameters given:

distance of the proton form the insulating sheet = 0.360mm

speed of the proton, $v_{x}$ = 990m/s

Surface charge density, σ = 2.34 x $10^{-9}$ C/ $m^{2}$

We need to calculate the speed at time, t = 7.0 * $10^{-8}$ s.

We know that the proton is moving parallel to the sheet, hence, we can say it is moving in the x direction, with a speed $v_{x}$ on the axis.

The electric force acting on the proton moves in the y direction, so this means it is moving with velocity $v_{y}$ in the y axis.

Hence, the resultant velocity of the proton is given by:

$v = \sqrt{v_{x} ^{2} + v_{y} ^{2}}$

$v_{x}$ = 990m/s from the question. We need to find $v_{y}$ and then the resultant velocity v.

Electric field is given in terms of surface charge density, σ as:

E = σ/ε0

where ε0 = permittivity of free space

=> $E = \frac{2.34 * 10^{-9} } {2 * 8.85418782 * 10^{-12} }$

E = 132 N/C

Electric Force, F is given in terms of Electric field:

F = eE

where e = electronic charge

=> F = ma = eE

∴ a = eE/m

where

a = acceleration of the proton

m = mass of proton

$a = \frac{1.60 * 10^{-19} * 132}{1.672 * 10^{-27} }$

a = 1.3 * $10^{10}$ m/ $s^{2}$

Therefore, at time, t = 7.0 * $10^{-8}$ , we can use one of the equations of linear motion to find the velocity in the y axis:

$a = \frac{v_{y} - v_{0}}{t} \\\\=> v_{y} = v_{0} + at$

$v_{y}$ = 0 + (1.3 * $10^{10}$ * 7.0 * $10^{-8}$ )

$v_{y}$ = 910 m/s

∴ $v = \sqrt{v_{x} ^{2} + v_{y} ^{2}}$

$v = \sqrt{990^{2} + 910^{2} }$

$v = \sqrt{1808200}$

v = 1344.69 m/s = $1.34 * 10^{3}$ m/s

8 0

4 years ago