2 years ago

How does the Moon affect Earth? Describe two examples. Edmentum answer

Physics

2 answers:

Gelneren [198K]2 years ago

4 0

Answer:

Gravity

Explanation:

anzhelika [568]2 years ago

4 0

Answer:

The Moon creates tides

As Earth spins on its own axis, gravity and centrifugal force keeps ocean waters at equal levels.

You might be interested in

4. An airplane maintains a constant acceleration of 4.0 m/s2 [E] as it speeds up from 16 m/s [E] to 28 m/s [E].

ki77a [65]

Answer:

gyvtu jyut

Explanation:

6 0

3 years ago

If u have a box with mass of 10kg and u push with a force of 200 N what is the acceleration of the box ?

AnnZ [28]

Answer:

20m/s²

Explanation:

force = mass*acceleration

acceleration = force ÷ mass

acceleration = 200N ÷ 10kg

acceleration = 20m/s²

5 0

3 years ago

A number of conditions are required for a population to be in Hardy-Weinberg equilibrium. Which of the following are correct des

S_A_V [24]

Answer: A, B, F

Explanation:

7 0

2 years ago

Read 2 more answers

How is the behavior of waves affected by a medium?

Vlad1618 [11]

They are slowed down.

even air is a medium and will slow down waves (slightly) compared to a vacuum/ space

if the wave hits the medium at an angle it can be 'bent' (refracted) like light through a glass prism

6 0

3 years ago

Read 2 more answers

PROBLEM 5 (Problem 4-145 in 7th edition) Consider a well-insulated horizontal rigid cylinder that is divided into two compartmen

kari74 [83]

Answer:

The answer is " $\bold{83.8^{\circ} \ C}$ ".

Explanation:

Formula for calculating the mass in He:

$\to m = \frac{PV}{RT}\\$

$= \frac{500 \times 1}{ 2.0769 \times (40 + 273)}\\\\ = \frac{500 }{ 2.0769 \times 313}\\\\ = \frac{500 }{ 650.0697}\\\\= 0.76914 \ Kg$

Formula for calculating the mass in $N_2$ :

$\to m = \frac{PV}{RT}\\$

$= \frac{500 \times 1}{ 0.2968 \times (120+ 273)}\\\\ = \frac{500 }{ 0.2968 \times 393}\\\\ = \frac{500 }{ 116.6424}\\\\= 4.2866\ Kg$

by using the temperature balancing the equation:

$T' = \frac{mcT (He) + mcT ( N_2 )}{ mc (He) + mc ( N_2)}$

$= \frac{0.76914 \times 3.1156 \times 313 + 4.2866 \times 0.743 \times393}{ 0.76914 \times 3.1156 + 4.2866 \times 0.743} \\\\ = 357 \ \ K \approx 83.8^{\circ} \ C$

3 0

2 years ago