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saveliy_v [14]
3 years ago
8

How does the Moon affect Earth? Describe two examples. Edmentum answer

Physics
2 answers:
Gelneren [198K]3 years ago
4 0

Answer:

Gravity

Explanation:

anzhelika [568]3 years ago
4 0

Answer:

The Moon creates tides

As Earth spins on its own axis, gravity and centrifugal force keeps ocean waters at equal levels.

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Density of copper is 8.96 g/cm3and density of zinc is 7.14 g/cm3. Brass is an alloy made of copper and zinc. You are given a sam
kvasek [131]

Answer:

The material cost for making one ton of the brass sample that I have is $8149.04.

Explanation:

Density of copper = 8.96 g/cm^3 = 8.96×10^-3 kg/cm^3

Price of copper = $6.13/kg

Price of copper per volume = 8.96×10^-3 kg/cm^3 × $6.13/kg = $0.0549/cm^3

Density of zinc = 7.14 g/cm^3 = 7.14×10^-3 kg/cm^3

Price of zinc = $1.8/kg

Price of zinc per volume = 7.14×10^-3 kg/cm^3 × $1.8/kg = $0.0129/cm^3

Price of brass per volume = 0.0549 + 0.0129 = $0.0678/cm^3

Density of brass I have is 8.32 g/cm^3 = 8.32 g/cm^3 × 1 kg/1000 g × 1 ton/1000 kg = 8.32×10^-6 ton/cm^3

Price = $0.0678/cm^3 ÷ 8.32×10^-6 ton/cm^3 = $8149.04/ton

5 0
3 years ago
Read 2 more answers
T or F A red-hot object is hotter than one that is while-hot?
leva [86]

Answer:

True. The two laws of thermal radiation state; 1) "Each square meter of a hotter object

Explanation:

5 0
2 years ago
PLEASE HALP ;w;
givi [52]
A haha snake e enajene. skskskksksks and
4 0
3 years ago
Why is the gravitational potential energy of an object 1 meter above Earth's surface more than its potential energy 1 meter abov
Umnica [9.8K]
I Believe The Answer Is C
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3 years ago
A parachutist falls 50.0 m without friction. When the parachute opens, he slows down at a rate of 67 m/s*2. If he reaches the gr
KIM [24]

Answer:

3.49 seconds

3.75 seconds

-43200 ft/s²

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

s=ut+\frac{1}{2}at^2\\\Rightarrow 50=0t+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow t=\sqrt{\frac{50\times 2}{9.81}}\\\Rightarrow t=3.19\ s

Time the parachutist falls without friction is 3.19 seconds

v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 9.81\times 50+0^2}\\\Rightarrow v=31.32\ m/s

Speed of the parachutist when he opens the parachute 31.32 m/s. Now, this will be considered as the initial velocity

v=u+at\\\Rightarrow 11=31.32+9.81t\\\Rightarrow t=\frac{11-31.32}{-67}=0.3\ s

So, time the parachutist stayed in the air was 3.19+0.3 = 3.49 seconds

s=ut+\frac{1}{2}at^2\\\Rightarrow \frac{s}{2}=0t+\frac{1}{2}\times a\times t^2\\\Rightarrow \frac{s}{2}=\frac{1}{2}at^2

s=ut+\frac{1}{2}at^2\\\Rightarrow \frac{s}{2}=u1.1+\frac{1}{2}\times a\times 1.1^2

Now the initial velocity of the last half height will be the final velocity of the first half height.

v=u+at\\\Rightarrow v=at

Since the height are equal

\frac{1}{2}at^2=u1.1+\frac{1}{2}\times a\times 1.1^2\\\Rightarrow \frac{1}{2}at^2=at1.1+\frac{1}{2}\times a\times 1.1^2\\\Rightarrow 0.5t^2-1.1t-0.605=0\\\Rightarrow 500t^2-1100t-605=0

t=\frac{11\left(1+\sqrt{2}\right)}{10},\:t=\frac{11\left(1-\sqrt{2}\right)}{10}\\\Rightarrow t=2.65, -0.45

Time taken to fall the first half is 2.65 seconds

Total time taken to fall is 2.65+1.1 = 3.75 seconds.

When an object is thrown with a velocity upwards then the velocity of the object at the point to where it was thrown becomes equal to the initial velocity.

v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{0^2-240^2}{2\times \frac{8}{12}}\\\Rightarrow a=-43200\ ft/s^2

Magnitude of acceleration is -43200 ft/s²

5 0
3 years ago
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