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saveliy_v [14]
3 years ago
8

How does the Moon affect Earth? Describe two examples. Edmentum answer

Physics
2 answers:
Gelneren [198K]3 years ago
4 0

Answer:

Gravity

Explanation:

anzhelika [568]3 years ago
4 0

Answer:

The Moon creates tides

As Earth spins on its own axis, gravity and centrifugal force keeps ocean waters at equal levels.

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Which statements describe acceleration? Check all that apply. Negative acceleration occurs when an object slows down in the posi
garik1379 [7]

Answer:

Negative acceleration occurs when the acceleration vector points to the left.

1. Object slowing down in the positive direction.

2. Object speeding up in the  negative direction.

Following six statements:

1. T

2. F

3. T

4. T

5. F

6. T

Check direction of acceleration vector.

7 0
3 years ago
A water wave has a frequency of 2 Hertz and a wavelength of 5 cm. Calculate it speed
Llana [10]

Answer: 0.1 m/s

Explanation:

Use formula,

v = f * w where, v is speed, f is frequency and w is wavelength.

Now,

v = 2 * 5 * 10 ^ -2 ( Remember to convert all the units to SI units. Here 5 cm becomes 5 * 10 ^ -2 m. )

v = 0.1 m/s.

8 0
3 years ago
The angular speed of digital video discs (DVDs) varies with whether the inner or outer part of the disc is being read. (CDs func
Kitty [74]

Answer:

α = 0.0135 rad/s²

Explanation:

given,

t = 133 min = 133 x 60 = 7980 s

angular speed varies from 570 rpm to 1600 rpm

now,

570 rpm = 570 \times \dfrac{2\pi}{60}

              = 59.69 rad/s

1600 rpm =  = 570 \times \dfrac{2\pi}{60}

              = 167.6 rad/s

using equation of rotational motion

ωf = ωi + αt    

167.6 = 59.7 + α x 7980

α  x 7980 = 107.9

α = 0.0135 rad/s²

8 0
3 years ago
H H H O H O N C C N C C H O H H O H H C H H H ALANINE GLYCINE
Trava [24]
i’m not 100 percent sure but I need points to ask questions good luck th
6 0
2 years ago
Force F=2.0N i - 3.0N k acts on a pebble with position vectorr=0.50m j - 2.0m k relative to the origin. In unit vector notation,
klasskru [66]

Answer with Explanation:

We are given that

Force acts on a pebble=2\hat{i}-3\hat{k} N

Position vector=r=0.5\hat{j}-2\hat{k} m

a.We have to find the resulting torque on the pebble about origin.

Torque=r\times F

Substitute the values then we get

Torque= (0.5j-2k)\times (2i-3k)

Torque=-k-1.5i-4jN-m

By using i\times j=k,j\times k=i,k\times i=j,j\times i=-k,k\times j=-i,i\times k=-j,i\times i=j\times j=k\times k=0

b.r=2i-3k

r-r_1=(0.5j-2k)-(2i-3k)=-2i+0.5j+k

Torque about point (2,0,-3)

\tau=(-2i+0.5j+k)\times (2i-3k)

\tau=-6j-k-1.5i+2j=-1.5i-4j-kN-m

6 0
3 years ago
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