Question

Two long parallel wires are 4 cm apart and carry currents of 2 A and 6 A in the same direction. calculate the force between the wire perimeter of wire length

Answer 1

Answer:

The  force per unit length of the wire is 6 x 10⁻⁵ N/m.

Explanation:

Given;

distance between the two parallel wires, r = 4 cm

current in the first wire, I₁ = 2 A

current in the second wire, I₂ = 6 A

The force per unit length of the wire is calculated as;

$\frac{f}{l} = \frac{\mu I_1 I_2}{2\pi r} \\\\\frac{f}{l} =\frac{4\pi \times 10^{-7} \ \times \ 2 \ \times \ 6}{2\pi \ \times \ 0.04} \\\\\frac{f}{l} = 6 \ \times \ 10^{-5} \ N/m$

Therefore, the  force per unit length of the wire is 6 x 10⁻⁵ N/m.