Answer:

Empirical formula = CH2O

Molecular formula = C6H12O6

Explanation:

According to this question, a compound is said to contain the following: 48.38g Carbon, 8.12g H, and 53.5g O.

First, we divide each mass value by its molar mass to convert to a mole value;

C = 48.38g ÷ 12g/mol = 4.03mol

H = 8.12g ÷ 1g/mol = 8.12mol

O = 53.5g ÷ 16g/mol = 3.34mol

Next, we divide each mole value by the lowest value (3.34mol)

C = 4.03mol ÷ 3.34 = 1.21

H = 8.12mol ÷ 3.34 = 2.43

O = 3.34mol ÷ 3.34 = 1

Approximately, the empirical ratio of CHO = 1:2:1, hence, the empirical formula is CH2O.

2. If the molar mass of the compound was determined to be 180.15 g/mol.

C = 12, H = 1, O = 16

(CH2O)n = 180.15

{12 + 1(2) + 16}n = 180.15

(12 + 2 + 16)n = 180.15

(30)n = 180.15

n = 180.15 ÷ 30

n = 6.005

Hence, (CH2O)n = (CH2O)6

Molecular formula = C6H12O6