For the equation BaCl2 + Na2SO4 → BaSO4 + 2NaCl, how many chlorine atoms are on the reactants side and on the products side?
2 answers:
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The hybridization for C in acetylene, HCCH, or C₂H₂ is 'sp'.
Discussion:
There are three different forms of hybridization -
- sp- The first occurs when two carbon atoms are triple linked.
- sp₂- When two carbon atoms are double-bonded to one another, this is known as sp₂.
- sp₃- When a single bond joins two carbon atoms, this is known as sp₃.
In the case of acetylene(HCCH or C₂H₂):
- The carbon atom requires additional electrons to establish four bonds with hydrogen and other carbon atoms in the synthesis of C₂H₂. One 2s₂ pair is consequently transferred to the vacant 2pz orbital. Each carbon has two sp hybrid orbitals after the 2s orbital in each atom combines with one of the 2p orbitals.
- As a result of the atoms' symmetrical alignment in a single plane, C₂H₂ possesses a linear molecular structure. Due to their lower electronegative nature than Hydrogen atoms, all Carbon atoms are situated near the center of the Lewis structure of C₂H₂.
H-C≡C-H
Therefore, it is concluded from the above discussion that the hybridization type of acetylene is 'sp'.
Learn more about hybridization here:
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Answer:
Limiting reactant: Oxygen
Explanation:
First write the balanced chemical equation:
given mass of methane =25g
molecular mass of methane=16g/mol
mole=1.5625mol
given mass of oxygen=50
molar mass of oxygen=32g/mol
mole=1.5625mol
from the above balanced equation it is clearly that,
1 mole of methane needs 2 moles of oxygen for complete reaction
Therefore,
1.5625 moles of methane needs 3.125 moles of oxygen for complete reaction but we have only 1.5625 moles of oxygen,
hence,
oxygen will be the limiting reactant and methane will be the excess reactant