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3 years ago

For the equation BaCl2 + Na2SO4 → BaSO4 + 2NaCl, how many chlorine atoms are on the reactants side and on the products side?

Chemistry

2 answers:

damaskus [11]3 years ago

8 0

Answer:

The balanced chemical reaction is written as follows:

bacl2 + na2so4 → baso4 + 2nacl

Therefore, the number of chlorine atoms in the reactants side and the products side would be 2 atoms in both sides which should be the case because the number of atoms in each side should have the same number.

Explanation:

Internet

lara [203]3 years ago

6 0

Answer:

fsadfdfsfds

Explanation:

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Describe a mechanical property of steel that characterizes its resistance to permanent deformation

strojnjashka [21]

The mechanical property of steel that characterizes its resistance to permanent deformation is ductility.

Am alloy is a substance prepared by adding one or more elements to a base or parent metal to obtain desirable properties.

Steel is an alloy of Iron and carbon in the composition of 99.8% and 0.2% respectively.

The mechanical or physical properties of steel include:

It is more malleable and ductile than iron.

It is harder and stronger.

it can withstand great stress and strain.

The ductility of a metal like steel is the ability of a metal to change its shape without breaking, that is, resistance to permanent deformation.

Therefore, the mechanical property of steel that characterizes its resistance to permanent deformation is ductility.

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8 0

2 years ago

After centrifugation of the sample, the student was not careful and some of the solid was transferred to the Erlenmeyer flask al

Tju [1.3M]

The fact that some of the solid was transferred would decrease the mass of the limiting reactant.

<h3>What is the limiting reactant?</h3>

We know that in a chemical reaction, there are at least two substances that are combined in order to give the product of the reaction. We also know that the product that we obtain must be in accordance to the stoichiometry of the reaction.

It is common to see that one of the reactants would be present in a very large amount while the other reactant would be present only in quite a small amount. The reactant that is present in a small amount is said to be the limiting reactant while the one that is present in the large amount is said to be the reactant that is in excess.

Having said this, we know that the mass of the limiting reactant can be obtained from the mass of the solid that is obtained after the reaction.

If we do not take out all of the solid from the centrifuge, the mass would not be accurately weighed and the mass of the limiting reactant would not be accurately determined.

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5 0

1 year ago

A mixture of 0.307 M Cl 2 , 0.465 M F 2 , and 0.706 M ClF is enclosed in a vessel and heated to 2500 K . Cl 2 ( g ) + F 2 ( g )

monitta

<u>Answer:</u> The equilibrium concentration of chlorine gas, fluorine gas and ClF gas is 0.159 M, 0.317 M and 1.002 M respectively.

<u>Explanation:</u>

We are given:

Initial concentration of chlorine gas = 0.307 M

Initial concentration of fluorine gas = 0.465 M

Initial concentration of ClF gas = 0.706 M

The given chemical equation follows:

$Cl_2(g)+F_2(g)\rightleftharpoons 2ClF(g)$

<u>Initial:</u> 0.307 0.465 0.706

<u>At eqllm:</u> 0.307-x 0.465-x 0.706+2x

The expression of $K_c$ for above equation follows:

$K_c=\frac{[ClF]^2}{[Cl_2][F_2]}$

We are given:

$K_c=20.0$

Putting values in above equation, we get:

$20.0=\frac{(0.706+2x)^2}{(0.307-x)(0.465-x)}\\\\x=0.148,0.993$

Neglecting the value of x = 0.993 because the equilibrium concentrations of chlorine and fluorine gases will become negative, which is not possible

So, equilibrium concentration of chlorine gas = (0.307 - x) = [0.307 - 0.148] = 0.159 M

Equilibrium concentration of fluorine gas = (0.465 - x) = [0.465 - 0.148] = 0.317 M

Equilibrium concentration of ClF gas = (0.706 + 2x) = [0.706 + 2(0.148)] = 1.002 M

Hence, the equilibrium concentration of chlorine gas, fluorine gas and ClF gas is 0.159 M, 0.317 M and 1.002 M respectively.

5 0

3 years ago

If 3.5 moles of nitrogen monoxide (NO) react with 6.0 moles of oxygen gas (O2), how many moles of the product can be formed and

jasenka [17]

Answer: -

4.25 mol of O₂ left as excess.

3.5 mol of NO₂ formed.

Explanation: -

Number of moles of NO taken = 3.5

Number of moles of O₂ taken = 6.0

The balanced chemical equation for this reaction is

2 NO+ O₂ → 2 NO₂

From the equation we can see that

2 mol of NO react with 1 mol of O₂

3.5 mol of NO react with $\frac{1 mol O2}{2 mol NO}$ x 3.5 mol NO

= 1.75 mol O₂

So Oxygen O₂ is in excess and NO is the limiting reagent.

Moles of O₂ left over = 6 - 1.75 =4.25 mol of O₂

From the balanced chemical equation we see

2 mol of NO gives 2 mol of NO₂

3.5 mol of NO gives $\frac2 mol NO2}{2 mol NO}$ x 3.5 mol NO

= 3.5 mol of NO₂

5 0

3 years ago

How many grams of coffee must evaporate from 350 g of coffee in a 100-g glass cup to cool the coffee and the cup from 95.0°C to

Natali5045456 [20]

Answer:

31.3 g

The answer is higher than the true answer.

Explanation:

By neglecting the heat lost by other processes, the energy conservation states that:

Qcooling + Qevaporate = 0

The cooling process happens without phase change, so the heat can be calculated by:

Qcooling = m*c*ΔT

Where m is the mass, c is the heat capacity (cwater = 4184 J/kg.K), and ΔT is the temperature variation (final - initial).

The evaporate process happen without changing of temperature (pure substance), and the heat can be calculated by:

Qevaporate = m*L

Where m is the mass evaporated and L is the heat of evaporation (2340000 J/kg).

0.350*4184*(45 - 95) + m*2340000 = 0

2340000m = 73220

m = 0.0313 kg

m = 31.3 g

Because of the assumptions made, the real mass is not that was calculated. There'll be changing mass when the coffee is cooling, and there'll be heat loses by other processes because the system is not isolated. Also, the substance is not pure. So, there'll be more factors at the energy equation, thus, the answer is higher than the true answer.

6 0

3 years ago