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3 years ago

For the equation BaCl2 + Na2SO4 → BaSO4 + 2NaCl, how many chlorine atoms are on the reactants side and on the products side?

Chemistry

2 answers:

damaskus [11]3 years ago

8 0

Answer:

The balanced chemical reaction is written as follows:

bacl2 + na2so4 → baso4 + 2nacl

Therefore, the number of chlorine atoms in the reactants side and the products side would be 2 atoms in both sides which should be the case because the number of atoms in each side should have the same number.

Explanation:

Internet

lara [203]3 years ago

6 0

Answer:

fsadfdfsfds

Explanation:

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0.03÷0.35 what is it rounding at least 3 digits

strojnjashka [21]

0.0857
Rounding off to three digits
Since 7 is more than five you change it to 0 and add 1 to 5
A: 0.086

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3 years ago

A(g) + 2B(g) → C(g) + D(g)

WITCHER [35]

Answer:

0.169

Explanation:

Let's consider the following reaction.

A(g) + 2B(g) ⇄ C(g) + D(g)

We can find the pressures at equilibrium using an ICE chart.

A(g) + 2 B(g) ⇄ C(g) + D(g)

I 1.00 1.00 0 0

C -x -2x +x +x

E 1.00-x 1.00-2x x x

The pressure at equilibrium of C is 0.211 atm, so x = 0.211.

The pressures at equilibrium are:

pA = 1.00-x = 1.00-0.211 = 0.789 atm

pB = 1.00-2x = 1.00-2(0.211) = 0.578 atm

pC = x = 0.211 atm

pD = x = 0.211 atm

The pressure equilibrium constant (Kp) is:

Kp = pC × pD / pA × pB²

Kp = 0.211 × 0.211 / 0.789 × 0.578²

Kp = 0.169

6 0

3 years ago

Which contains elements with similar properties in the periodic table? A.) a period B.) a column C.) a row

zysi [14]

b............................................

3 0

3 years ago

Read 2 more answers

A sample of gas contains 0.1500 mol of HCl(g) and 7.500×10-2 mol of Br2(g) and occupies a volume of 9.63 L. The following reacti

Furkat [3]

Answer:

9.63 L.

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

$2HCl(g) + Br_2(g)\rightarrow 2HBr(g) + Cl_2(g)$

So the consumed amounts of hydrochloric acid and bromine are the same to the beginning based on:

$n_{Br_2}^{consumed}=0.1500molHCl*\frac{1molBr_2}{2molHCl}=0.075molBr_2$

In such a way, the yielded moles of hydrobromic acid and chlorine are:

$n_{HBr}=0.1500molHCl*\frac{2molHBr}{2molHCl}=0.1500molHBr \\n_{Cl_2}=0.1500molHCl*\frac{1molCl_2}{2molHCl}=0.075molCl_2$

Thus, the volume of the sample, after the reaction is the same as no change in the total moles is evidenced, that is 9.63L.

Best regards.

7 0

3 years ago

Identify the element in C6H12O6 that allows it to be classified as an organic compound.

LenaWriter [7]

Answer:

i dont know lol

Explanation:

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3 years ago