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Marina86 [1]
2 years ago
12

A flywheel of mass 182 kg has an effective radius of 0.62 m (assume the mass is concentrated along a circumference located at th

e effective radius of the flywheel).
(a) How much work is done to bring this wheel from rest to a speed of 120 rev/min in a time. interval of 30.0 s?
(b) What is the applied torque on the fly-wheel (assumed constant)?
Physics
1 answer:
musickatia [10]2 years ago
4 0

Answer:

A)5524J,

B) 29.2Nm

Explanation:

This question can be treated using work- energy theorem

Work= change in Kinectic energy

W= Δ KE

Work= difference between the final Kinectic energy and intial Kinectic energy.

We know that

Kinectic energy= 1/2 mv^2 .............eqn(1)

This can be written in term of angular velocity, as

KE= 1/2 I

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If a population of 1,000 individuals has 160 rr genotypes, what is the frequency of the rr genotype?
lesya692 [45]
The frequency of a genotype is how often it occurs. This can be obtained by:
number of occurrences / total population
= 160 / 1000
= 0.16 or 16%
7 0
3 years ago
A small bolt with a mass of 41.0 g sits on top of a piston. The piston is undergoing simple harmonic motion in the vertical dire
EleoNora [17]

Answer:

Amplitude will be equal to 0.091 m

Explanation:

Given mass of the slits = 41 gram = 0.041 kg

Frequency f = 1.65 Hz

So angular frequency \omega =2\pi f=2\times 3.14\times 1.65=10.362rad/sec

Angular frequency is equal to \omega =\sqrt{\frac{k}{m}}

10.362 =\sqrt{\frac{k}{0.041}}

Squaring both side

107.371 ={\frac{k}{0.041}}

k = 4.40 N/m

For vertical osculation

mg=kA

0.041\times 9.8=4.40\times A

A = 0.091 m

So amplitude will be equal to 0.0391 m

8 0
3 years ago
Which of the following is necessary for the greenhouse effect?
Mice21 [21]
It is the atmosphere

3 0
3 years ago
Express the length of a marathon run of<br> 26 mi 385 yd in meters.<br> Answer in units of m.
hjlf

Answer:

1 mi = 5280 ft  * 12 in/ft = 63360 in

A convenient conversion factor (to remember) is 1 m = 39.37 in

63360 in / (39.37 in / m) = 1609.3 m

26 mi + 285 m = 26 * 1609.3 + 385 = 42,228 m

6 0
2 years ago
A hypothetical planet has a mass one-third of and a radius three times that of Earth. What is the acceleration due to gravity on
kap26 [50]

Answer:

F) The acceleration due to gravity is g/27

Explanation:

According to Newton gravitational law, the gravitational acceleration is directly proportional to the planet mass and inversely proportional to the square of distance.

Since our new planet has a mass of one-third of Earth's and radius 3 times of Earth's. This means the new planet is lighter and further away from the distance. This means g is first reduced by 3 due to smaller mass and then reduced by 9 due to square of 3 times the distance.

The gravitational acceleration on this new planet must be

\frac{g/3}{3^2}

\frac{g}{27}

So F) is the correct answer

6 0
2 years ago
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