Answer:82.7% C and 17.3% H
Explanation:
C4 = 12.0107g/mol x 4 = 48.0428 g/mol
H10 = 1.00794 g/mol x 10 = 10.0794 g/mol
Molar Mass of Butane, C4H10 = 48.0428 g/mol + 10.0794 g/mol= 58.1222 g/mol
percent composition of Carbon is = ( mass of carbon contained in butane / molar mass of Butane) x 100
=(48.0428 /58.1222) x 100% = 0.8265 x 100
=82.65% =82.7% of Carbon.
Percent composition of Hydrogen = (mass of Hydrogen contained in Butane / molar mass of Butane )x 100
( 10.0794/58.122 ) x 100% =0.1734 x 100
= 17.3% OF Hydrogen.
Explanation:
The radioactive scattering technique is called radioactive degradation. For each radioactive isotope, the natural radioactive cycle is special and is determined by a period of time termed a half-life. One half-life was its time needed to experience radioactivity for half of both the radioactive nuclei.
Carbon dioxide + water → glucose + oxygen + water
Dry, white powder, soluble in water to form a slightly basic solution
Answer: 6.77*1022 Molecules
Explanation: :)
