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Ulleksa [173]
3 years ago
5

F a roller coaster at six flags had a car with a mass of 400 kg and a velocity of 50m/s, calculate the kinetic energy of the rol

ler coaster
Physics
1 answer:
NemiM [27]3 years ago
4 0

Kinetic Energy = (1/2) (mass) (speed)²

KE = (1/2) (400 kg) (50 m/s)²

KE = (200 kg) (2500 m²/s²)

KE = 500,000 kg-m²/s²

<em>KE = 500,000 Joules</em>

KE = 1/2 Mega-Joule

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3 years ago
Jodi made a list about electric current to help her study for a test. 1) Movement of electrons is continuous in a current. 2) El
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Answer:

Rate at which current flows is measured in amperes

Explanation:

The rate of flow of electrons constitutes the current. The electrons flow from lower electric potential to higher electric potential. When there is no potential difference then no electron will flow. The direction of the current and the electron are in opposite direction.

The direction of electron from the negative terminal to the positive terminal. The direction of current is from the positive terminal to the negative terminal.The current is measured in ampere.    

The expression for current and the charge is as;

I=\frac{q}{t}

Here, q is the charge, t is the time taken and I is the current.

According to the given problem, Jodi made a list about electric current to help her study for a test. He described that electrons move from areas of low to high electric potential, voltage causes current to flow and movement of electrons is continuous in a current.

But he did error. It should be "rate at which charges flow" instead of rate at which current flow.

Therefore, the option (4) is correct.

4 0
3 years ago
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When you go on a hunting trip, you should leave a hunting plan with someone you trust. What information should the plan include?
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A man walks along a straight path at a speed of 4 ft/s. A searchlight is located on the ground 6 ft from the path and is kept fo
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We are given that,

\frac{dx}{dt} = 4ft/s

We need to find \frac{d\theta}{dt} when x=8ft

The equation that relates x and \theta can be written as,

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Differentiating each side with respect to t, we get,

\frac{dx}{dt} = \frac{dx}{d\theta} \cdot \frac{d\theta}{dt}

\frac{dx}{dt} = (6sec^2\theta)\cdot \frac{d\theta}{dt}

\frac{d\theta}{dt} = \frac{1}{6sec^2\theta} \cdot \frac{dx}{dt}

Replacing the value of the velocity

\frac{d\theta}{dt} = \frac{1}{6} cos^2\theta (4)^2

\frac{d\theta}{dt} = \frac{8}{3} cos^2\theta

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