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Ulleksa [173]
3 years ago
5

F a roller coaster at six flags had a car with a mass of 400 kg and a velocity of 50m/s, calculate the kinetic energy of the rol

ler coaster
Physics
1 answer:
NemiM [27]3 years ago
4 0

Kinetic Energy = (1/2) (mass) (speed)²

KE = (1/2) (400 kg) (50 m/s)²

KE = (200 kg) (2500 m²/s²)

KE = 500,000 kg-m²/s²

<em>KE = 500,000 Joules</em>

KE = 1/2 Mega-Joule

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3 years ago
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Four point masses of 3.0 kg each are arranged in a square on masslessrods. The length of a side of the square is 0.50m. What is
Zigmanuir [339]

Answer:

Part a)

I = 1.5 kg m^2

Part b)

I = 0.75 kg m^2

Part c)

I = 1.5 kg m^2

Explanation:

Part a)

Moment of inertia of the system about an axis passing through B and C is given as

I = mL^2 + mL^2 + m(0) + m(0)

I = 2mL^2

I = 2(3 kg)(0.50^2)

I = 1.5 kg m^2

Part b)

Moment of inertia of the system about an axis passing through A and C is given as

I = m(0^2) + m(\frac{L}{\sqrt2})^2 + m(0) + m(\frac{L}{\sqrt2})^2

I = 2m\frac{L^2}{2}

I = (3 kg)(0.50^2)

I = 0.75 kg m^2

Part c)

Moment of inertia of the system about an axis passing through the center of the square and perpendicular to the plane of the square

I = m(\frac{L}{\sqrt2})^2 + m(\frac{L}{\sqrt2})^2 + m(\frac{L}{\sqrt2})^2 + m(\frac{L}{\sqrt2})^2

I = 4m\frac{L^2}{2}

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8 0
3 years ago
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Answer:

d= 64.7 km

\theta = 40.9^{o}

displacement vector=r_xi + r_yj =  48.9i + 42.4j

Explanation:

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during 1st flight

r_1 x = 40*cos60

r_1 x = 20 km

r_1 y = 40*sin60

r_1 y = 34.64 km

during 2nd flight

r_2 x = 30*cos15

r_2 x = 28.9 km

r_2 y = 30*sin15

r_2 y = 7.76 km

the two component of r are:

r_x = r_1x + r_2x = 20 + 28.9 = 48.9 km

r_y = r_1y + r_2y = 34.64 + 7.76 = 42.4 km

Geographical Direction \theta = tan^{-1}\frac{r_y}{r_x} [tex]\theta = 40.9^{o}

Displacement d= \sqrt{r_x^2 + r_y^2}

                     d = \sqrt{48.9^2+42.4^2} = 64.7 km

d= 64.7 km

displacement vector=r_xi + r_yj =  48.9i + 42.4j

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3 years ago
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Answer:   A

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