T = ?
v1 = 0mph
v2 = 60mph
a = 8.7mph/s

Therefore, it takes 6.90 seconds for Jill to accelerate from 0 to 60 miles per hour.
Answer:
System inputs and outputs fluctuate around a stable average so the system does not move far from its average condition.
Explanation:
Steady-state equilibrium can also be called dynamic equilibrium. The main difference between the two is the type of system we are considering. When a system is closed, and it attains equilibrium, there is no transfer of energy. In the case of an open system, even if the system achieves equilibrium there will be some transfer of energy but it will not deviate far from it's equilibrium point, that is, it will be in a steady-state.
The electric field strength is 
Explanation:
The strength of the electric field produced by a single point charge is given by:

where
is the Coulomb's constant
q is the magnitude of the charge
r is the distance from the charge at which the field strength is calculated
For the charge in the problem, we have:
is the charge

Therefore, the electric field strength is

Learn more about electric fields:
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Hi there! Lets see!
- m is mass, and its units are kg
- k is the elastic constant measured in newtons per meter (N/m), or kilograms per second squared kg/s²
Therefore:
![\sqrt{\dfrac{m}{k}} =\sqrt{\dfrac{[kg]}{[\dfrac{kg}{s^2}]}} =\sqrt{\dfrac{[kg]}{[kg]}\cdot s^2} = \sqrt{[s]^2} = s](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cdfrac%7Bm%7D%7Bk%7D%7D%20%3D%5Csqrt%7B%5Cdfrac%7B%5Bkg%5D%7D%7B%5B%5Cdfrac%7Bkg%7D%7Bs%5E2%7D%5D%7D%7D%20%20%3D%5Csqrt%7B%5Cdfrac%7B%5Bkg%5D%7D%7B%5Bkg%5D%7D%5Ccdot%20s%5E2%7D%20%3D%20%5Csqrt%7B%5Bs%5D%5E2%7D%20%3D%20s)
The period is given in seconds so the formula is dimensionally correct.