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-BARSIC- [3]
3 years ago
12

Clouds in our atmosphere cause us to see the different phases of the moon.

Physics
2 answers:
krok68 [10]3 years ago
8 0

Answer:

False

Explanation:

:)

Alina [70]3 years ago
4 0

Answer:

The answer is false

Explanation:

The clouds have nothing to do with the changes in the phases of the moon but, rather the postioning of the sun and the moon regarding revolution and the spinning of the earth on it axis.

I hope this helps you good luck and have a good day.

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jill's car has a maximum acceleration of 8.7 miles per hour per second. how many seconds does it take her to acceleration from 0
amm1812
T = ?
v1 = 0mph
v2 = 60mph
a = 8.7mph/s

a =  \frac{v2 - v1}{t}
 \\ t =  \frac{v2-v1}{a}
 \\ t =  \frac{60mph - 0mph}{8.7mph/s}
 \\ t = 6.90s

Therefore, it takes 6.90 seconds for Jill to accelerate from 0 to 60 miles per hour.
4 0
4 years ago
Formula: KE = 1/2 my?
9966 [12]

Answer:

22400 Joules

Explanation:

Apply the formula:

KE = 1/2 . 40 . 1120

KE = 20 . 1120

KE = 22400 Joules

3 0
3 years ago
Which statement BEST describes the condition of steady-state equilibrium? - System slowly adjusts to long-term changes in input
krok68 [10]

Answer:

System inputs and outputs fluctuate around a stable average so the system does not move far from its average condition.

Explanation:

Steady-state equilibrium can also be called dynamic equilibrium. The main difference between the two is the type of system we are considering. When a system is closed, and it attains equilibrium, there is no transfer of energy. In  the case of an open system, even if the system achieves equilibrium there will be some transfer of energy but it will not deviate far from it's equilibrium point, that is, it will be in a steady-state.

6 0
3 years ago
4. What is the electric field strength 1.4 nm from a charge of 4.7 cC?
pentagon [3]

The electric field strength is 2.16\cdot 10^{26} N/C

Explanation:

The strength of the electric field produced by a single point charge is given by:

E=k\frac{q}{r^2}

where

k=8.99\cdot 10^9 Nm^{-2}C^{-2} is the Coulomb's constant

q is the magnitude of the charge

r is the distance from the charge at which the field strength is calculated

For the charge in the problem, we have:

q=4.7 cC = 0.047 C is the charge

r=1.4 nm = 1.4\cdot 10^{-9} m

Therefore, the electric field strength is

E=(8.99\cdot 10^9)\frac{0.047}{(1.4\cdot 10^{-9})^2}=2.16\cdot 10^{26} N/C

Learn more about electric fields:

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

5 0
3 years ago
Check the correctness of formula t=2π √m/k, dimensionally​
pantera1 [17]

Hi there! Lets see!

  • m is mass, and its units are kg
  • k is the elastic constant measured in newtons per meter (N/m), or kilograms per second squared kg/s²

Therefore:

\sqrt{\dfrac{m}{k}} =\sqrt{\dfrac{[kg]}{[\dfrac{kg}{s^2}]}}  =\sqrt{\dfrac{[kg]}{[kg]}\cdot s^2} = \sqrt{[s]^2} = s

The period is given in seconds so the formula is dimensionally​ correct.

4 0
3 years ago
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