Explanation:
Hole. Hole. Different notes can be played on the flute by blocking holes. ...
Drum skin. Drum skin. Hitting the bongo drum makes its tight elastic skin vibrate.
String. String. ...
Sound. hole. ...
Bow. Bow.
Answer:

Explanation:
The inital electrostatic force between the two spheres is given by:

where
is the initial force
k is the Coulomb's constant
q1 and q2 are the charges on the two spheres
r is the distance between the two spheres
The problem tells us that the two spheres are moved from a distance of r=20 cm to a distance of r'=10 cm. So we have

Therefore, the new electrostatic force will be

So the force has increased by a factor 4. By using
, we find

The spring should have a greater displacement .
Greater spring constant = the more difficult it is to stretch a spring , due to stiffness.
Answer:
a ) 24 m/s
Explanation:
Given,
Frequency ( f ) = 6 Hz
Wavelength ( λ ) = 4 m
To find : Speed ( v ) = ?
Formula : -
v = f x λ
v
= 4 x 6
= 24 m/s
Therefore, the speed of a wave that has a frequency of 6 Hz and a wavelength of 4 m
is 24 m/s.