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Reptile [31]
3 years ago
15

A man is lifting a piano that weighs 800 N through a distance of 10 meters using a pulley system. The man pulls the rope a total

distance of 100m. What force does the man need to apply to the rope?
Physics
1 answer:
Flauer [41]3 years ago
3 0

Answer:

The force the man applied is 80 N

Explanation:

weight of the load, L = 800 N

distance traveled by the load, a = 10 m

distance traveled by the effort, b = 100 m

Output work = load x distance moved by the load

Output work = 800 x 10 = 8000 J

Input work = Effort x distance moved by effort

Input work = Effort x 100 m

Assuming an ideal machine; no friction effect, the input work will be equal to output work.

Effort x 100 m = 8000 J

Effort = 8000 / 100

Effort = 80 N

Therefore, the force the man applied is 80 N

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True or false 6.02x10^23 atoms of oxygen have a mass of 16g ?
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Answer:

True

Explanation:

The atomic mass of oxygen is 16amu, which means the <em>molar mass</em>, the mass of one mole of oxygen atoms (1 mole = 6.02x10²³), is 16g.

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A car is traveling at 70 km/h. It then uniformly decelerates to a complete stop in 12 s. Find its acceleration ( in m/s2 ).
Yakvenalex [24]

Answer:

Acceleration will be -1.620m/sec^2

Explanation:

We have given initial speed of the car is 70 km/hr

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It is given that car stops in 12 sec

So final speed of the car v = 0 m/sec

Time t = 12 sec

From first equation of motion v = u+at

So 0=19.444+a\times 12

a=\frac{-19.444}{12}=-1.620m/sec^2 ( negative sign indicates that speed of the car will constantly decrease )

5 0
3 years ago
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Suppose you have a rock that, when it solidifies, contains 1 microgram of a radioactive isotope. How much of this isotope remain
algol13

Answer:

d) 1/32 microgram

Explanation:

First half life is the time at which the concentration of the reactant reduced to half.

Second half reaction is the time at which the remaining concentration reduced to half or the initial concentration reduced to 1/4.

Third half life is the time at which the remaining concentration reduced to half or the initial concentration reduced to 1/8.

Forth half life is the time at which the remaining concentration reduced to half or the initial concentration reduced to 1/16.

Fifth half life is the time at which the remaining concentration reduced to half or the initial concentration reduced to 1/32.

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After 5 half-lives, the mass should reduce to 1/32 of the original.

So the concentration left = 1/32 of 1 microgram = 1/32 microgram

7 0
3 years ago
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