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Reptile [31]
3 years ago
15

A man is lifting a piano that weighs 800 N through a distance of 10 meters using a pulley system. The man pulls the rope a total

distance of 100m. What force does the man need to apply to the rope?
Physics
1 answer:
Flauer [41]3 years ago
3 0

Answer:

The force the man applied is 80 N

Explanation:

weight of the load, L = 800 N

distance traveled by the load, a = 10 m

distance traveled by the effort, b = 100 m

Output work = load x distance moved by the load

Output work = 800 x 10 = 8000 J

Input work = Effort x distance moved by effort

Input work = Effort x 100 m

Assuming an ideal machine; no friction effect, the input work will be equal to output work.

Effort x 100 m = 8000 J

Effort = 8000 / 100

Effort = 80 N

Therefore, the force the man applied is 80 N

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You accelerate from 2m/s to 6m/s while traveling a distance of 2m; what was your acceleration?
nata0808 [166]

Answer:

The acceleration is 8 m/s²

Explanation:

The given parameters are;

The initial velocity, u = 2 m/s

The final velocity, v = 6 m/s

The distance the acceleration took place, s = 2 m

The acceleration, a, can be found from the following kinematic equation;

v² = u² + 2·a·s

By substituting the values, we have;

6² = 2² + 2 × a × 2

6² - 2² = 2 × a × 2

32 = 4·a

a = 32/4 = 8 m/s²

The acceleration, a, of the given motion = 8 m/s².

7 0
3 years ago
A pelican flying along a horizontal path drops a fish from a height of 4.7 m. The fish travels 9.3 m horizontally before it hits
slavikrds [6]

Answer:

(A) 9.5 m/s

(B) 5.225 m

Explanation:

vertical height (h) = 4.7 m

horizontal distance (d) = 9.3 m

acceleration due to gravity (g) = 9.8 m/s^{2}

initial speed of the fish (u) = 0 m/s

(A) what is the pelicans initial speed ?

  • lets first calculate the time it took the fish to fall

s = ut + (\frac{1}{2}) at^{2}

since u = 0

s =  (\frac{1}{2}) at^{2}

t = \sqrt{\frac{2s}{a} }

where a = acceleration due to gravity and s = vertical height

t = \sqrt{\frac{2 x 4.7 }{9.8} } = 0.98 s

  • pelicans initial speed = speed of the fish

speed of the fish = distance / time = 9.3 / 0.98 = 9.5 m/s

initial speed of the pelican = 9.5 m/s

(B) If the pelican was traveling at the same speed but was only 1.5 m above the water, how far would the fish travel horizontally before hitting the water below?

vertical height = 1.5 m

pelican's speed = 9.5 m/s

  • lets also calculate the time it will take the fish to fall

s = ut + (\frac{1}{2}) at^{2}

since u = 0

s =  (\frac{1}{2}) at^{2}

t = \sqrt{\frac{2s}{a} }

where a = acceleration due to gravity and s = vertical height

t = \sqrt{\frac{2 x 1.5 }{9.8} } = 0.55 s

 

distance traveled by the fish = speed x time = 9.5 x 0.55 = 5.225 m

8 0
3 years ago
A reducing elbow in a horizontal pipe is used to deflect water flow by an angle θ = 45° from the flow direction while accelerati
sleet_krkn [62]

Answer:

915 N is the anchoring force needed to hold the elbow in place.

Explanation:

Momentum equation:

∑

7 0
3 years ago
When compared to strong nuclear force , gravitational force is
Nina [5.8K]
Gravitational force is very weaker;
6 0
3 years ago
Read 2 more answers
You carry a 20 N bag of dog food up a 6.0 m flight of stairs. How much work was done?
MariettaO [177]
Answer:
120 J

Explanation:


Formula Of Work= Work= Force x Displacement

Work= 20 N x 6.0

Work= 120 Joules

The reason I put joules because the Unit of work is joules
8 0
2 years ago
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