The time taken for him to move the bin 6.5 m is 2.30 s.
The given parameters;
- <em>weight of the load, w = 557 N</em>
- <em>force applied , F = 410 N</em>
- <em>angle of force, = 15°</em>
- <em>coefficient of kinetic friction = 0.46</em>
- <em>distance moved, d = 6.5 m</em>
The net horizontal force on the recycling bin is calculated as follows;

where;
- <em>m is the mass of the recycling bin</em>
- <em />
<em> is the frictional force </em>
W = mg

The net horizontal force on the recycling bin is calculated as;

The time taken for him to move the bin 6.5 m is calculated as follows;

Thus, the time taken for him to move the bin 6.5 m is 2.30 s.
Learn more here:brainly.com/question/21684583
Answer:
250,000
Explanation:
<h2> </h2>
<h2>formula = ( F=ma </h2>
- F=1500N
- a=6m/s^2
- F= ma
- m=?
- 1500/6 = m
- m=250 kg
- 1kg =1000gm so 250kg =250,000gm
- m =250×10^3 gm
If a point has 40 J of energy and the electric potential is 8 V, the charge must be: A. 5 C
<u>Given the following the details;</u>
- Electric potential = 8 Volts
To find the quantity of charge;
Mathematically, the quantity of charge with respect to electric potential is given by the formula;

Substituting the values into the formula, we have;

<em>Quantity of charge = 5 Coulombs</em>
Therefore, the quantity of charge must be <em>5 Coulombs.</em>
Find more information: brainly.com/question/21808222
Please mark brainliest you answer is B).
Have a good night!