Answer:
Kc = Kc = 8.0 * 10^9
Kp = 5.5 *10^5
Explanation:
Step 1: Data given
Temperature = 25.0 °C
Number of moles Fe = 1.0 moles
Number of moles O2 = 1.0 * 10^-3 moles
Number of moles Fe2O3 = 2.0 moles
Volume = 2.0 L
Step 2: The balanced equation
4Fe(s) + 3O2(g) ⇌ 2Fe2O3(s)
Step 3: Calculate molarity
Molarity = moles / volume
[Fe] = 1.0 moles / 2.0 L
[Fe] = 0.5 M
[O2] = 0.001 moles / 2.0 L
[O2] = 0.0005 M
[Fe2O3] = 2.0 moles / 2.0 L
[Fe2O3] = 1.0 M
Step 4: Calculate Kc
Kc =1/ [O2]³
Kc = 1/0,.000000000125
Kc = 8.0 * 10^9
Step 5: Calculate Kp
Kp = Kc*(R*T)^Δn
⇒with Kc = 8.0*10^9
⇒with R = 0.08206 L*atm /mol*K
⇒with T = 298 K
⇒with Δn = -3
Kp = 8.10^9 *(0.08206 * 298)^-3
Kp = 5.5 *10^5
The answer is a identical
Answer:
New volume V2 = 120.4 ml
Explanation:
Given:
Pressure P1 = 1.12 atm
New pressure P2 = 1.12[1+0.25] = 1.4 atm
Old volume V1 = 150.5 ml
Find:
New volume V2
Computation:
P1V1 = P2V2
(1.12)(150.5) = (1.4)(V2)
V2 = 120.4 ml
New volume V2 = 120.4 ml
The H⁺ ion concentration can be calculated from pH values using the following equation:
![pH=-log[H⁺]](https://tex.z-dn.net/?f=pH%3D-log%5BH%E2%81%BA%5D)
1.) Given pH = 2
Using the above equation, 2 = - log [H⁺]
Therefore, [H⁺] = 10⁻² mol/L
2.) Given pH = 6
Using the same equation, we have 6 = - log [H⁺]
Hence, [H⁺] = 10⁻⁶ mol/L
3.) Taking the ratio of [H⁺] for pH = 2 and pH = 6, we have
= 10⁴
So, there are 10,000 times more H⁺ ions in a solution of pH = 2 than that of pH = 6.
Answer:
Yes, because each element has the same number of protons and electrons.
Explanation:
