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alexgriva [62]
2 years ago
9

Use your answers from questions 1–3 as the basis for the first section of your lab report. This section provides your reader wit

h background information about why you conducted this experiment and how it was completed. Outline the steps of the procedure in full sentences. It also provides potential answers (your hypothesis/es) relative to what you expected the experiment to demonstrate. This section should be 1–3 paragraphs in length.
Chemistry
1 answer:
Kipish [7]2 years ago
8 0

Answer:

so in all my hypothesis was correct. It is also true that the more mass on the carr the faster and farther it goes. if i were to do it differently i would probably add more washers to increase the mass and maybe test the 2nd law of motion.

Explanation:

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how much heat is required to change the temperature of 10 grams of water from 4 degrees Celsius to 8 degrees celsius?
Rufina [12.5K]

Answer:

0.167 kJ

Explanation:

The rise in the temperature of a substance or a material caused by absorbing the heat energy is given in an equation Q = m x c x ∆T, where:

Q is an amount of heat absorbed ( in Joules)

m is the mass of the substance (in kilograms)

c is specific heat capacity ( amount of heat per unit mass required to raise the temperature by one degree Celsius)

∆T is the difference in the temperature

So, m=10g which is 0.01kg; ∆T is 8°C - 4°C= 4°C; and c for water is constant value and is equal to 4186 J/kg C.

Now it's easy to calculate the amount of energy: Q=0.01x4186x4 which equals to 167.44 J, which is approximately 0.167 kJ

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2 years ago
Steel:<br> Propane:<br> Calcium chloride:<br> Water:
kondor19780726 [428]
What is the question
4 0
2 years ago
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How many grams of Cl are in 515 g CaCl2 ? mass:
Lelechka [254]

The explanation is in the picture

3 0
1 year ago
The Henry's Law constant of methyl bromide, CH3Br, is k = 0.159 mol/(L ⋅ atm) at 25°C. What is the solubility of methyl bromide
dedylja [7]

Answer:

.055 mol/L

Explanation:

Henry's Law is about solubility of a gas in a liquid which is dependent on the partial pressure of gas above the liquid . According to it

C = k P where C is concentration of gas in the liquid , k is henry's constant and P is partial pressure of the gas .

Given k = .159 mol/L.atm

P = 265 mm of Hg

= 265 / 760

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C = kP

= .159 x .34868

= .055 mol/L

3 0
2 years ago
The hydrides of group 5A are NH3, PH3, AsH3, and SbH3. Arrange them from highest to lowest boiling point.
Anestetic [448]

Explanation:

The hydrides of group 5A show an increase in boiling point from PH_{3} to BiH_{3}. But boiling point of NH_{3} is higher than rest of the hydrides of group 5A.

This is because electronegativity of nitrogen is higher than hydrogen. So, it will attract electrons of hydrogen more towards itself. Thus, polarity will develop between nitrogen and hydrogen bond. As a result, NH_{3} will undergo strong hydrogen bonding.

In order to break this N-H bond, high temperature is required. Thus, boiling point of NH_{3} will be high.

On the other hand, on moving down the group there will be an increase in mass. Thus, there will be increase in Vander waals forces of attraction and as a result, there will be increase in boiling point from  PH_{3} to BiH_{3}.

Whereas the boiling point of NH_{3}  is higher than those of PH_{3} and AsH_{3} but lower than SbH_{3} and BiH_{3} because higher Vander waals forces of attraction more than compensates the increase in boiling point of NH_{3} because of hydrogen bonding.

Thus, the order from highest to lowest boiling point for hydrides of group 5A are as follows.

     BiH_{3} > SbH_{3} > NH_{3} > AsH_{3} > PH_{3}    

7 0
3 years ago
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