All categories

2 years ago

After concluding his research, which statements would Virchow agree with? Check all that apply.

Physics

2 answers:

Viktor [21]2 years ago

8 0

Answer:

The answer is A and B

Explanation: I took the exam and i got it right

satela [25.4K]2 years ago

3 0

Answer:

(A) Living things can only come from living things.

(B) Cells come from pre-existing cells.

Explanation:

i just answered this on e d g e n u i t y.

hope this helps <3

You might be interested in

A 1000 kg whale is dropped at a rate of 9.8 m/s2. With what force will it hit the ground?

anygoal [31]

Answer:

If your teacher doesn't ask u to turn kg into lb:

F = m × a

F = 1000kg × 9,8m/s2

F = 9800N

If she does ask u then:

m= 1000kg × 2,206 = 2204.62lb

use the same formula

7 0

2 years ago

As a glacier melts, the volume V of the ice, measured in cubic kilometers, decreases at a rate modeled by the differential equat

vovangra [49]

Solve the differential equation:

dV/dt = k V → 1/V dV/dt = k

→ d/dt [ln(V)] = k

→ ln(V) = k t + C

→ V (t )= exp(k t + C ) = C exp(k t ) = C e ᵏᵗ

At t = 0, the glacier has volume 400 km³ of ice, so

V (0) = 400 → C e⁰ = C = 400

Find when the glacier's volume is 300 km³:

V (t ) = 400 e ᵏᵗ = 300 → e ᵏᵗ = 3/4

→ k t = ln(3/4)

→ t = 1/k ln(3/4)

At this time, the volume is decreasing at a rate of 15 km³/yr, so

V ' (t ) = C k e ᵏᵗ → V ' (1/k ln(3/4)) = 400 k exp(k × 1/k ln(3/4)) = -15

→ 3/4 k = -3/80

→ k = -1/20

Then the volume V (t ) of the glacier at time t is

V (t ) = 400 exp(-1/20 t )

7 0

2 years ago

4. A rock is thrown from the edge of the top of a 100 m tall building at some unknown angle above the horizontal. The rock strik

nikklg [1K]

Answer:

Explanation:

Let the velocity of projectile be v and angle of throw be θ.

The projectile takes 5 s to touch the ground during which period it falls vertically by 100 m

considering its vertical displacement

h = - ut +1/2 g t²

100 = - vsinθ x 5 + .5 x 9.8 x 5²

5vsinθ = 222.5

vsinθ = 44.5

It covers 160 horizontally in 5 s

vcosθ x 5 = 160

v cosθ = 32

squaring and adding

v²sin²θ +v² cos²θ = 44.4² + 32²

v² = 1971.36 + 1024

v = 54.73 m /s

5 0

3 years ago

Read 2 more answers

A reconnaissance plane flies 605 km away from

kolezko [41]

Answer:

$v_{avg} =$ 355 m/s

Explanation:

Distance = 605 km

Initial speed = $v_{i}$ = 284 m/s

Final velocity = $v_{f}$ = 426 m/s

Average speed = ?

There is two method two find average speed. In first method, using 3rd equation of motion, we find acceleration.

$2as = v_{f}^{2}+v_{i}^{2}$

Then using first equation of motion, we find time

$v_{f} = v_{i}+at$

Then using the formula of average velocity, we find average velocity

$v_{avg}=\frac{total-distance}{total-time}$

Second method is very simple

$v_{avg}=\frac{v_{f}+v_{i} }{2}$

$v_{avg}=\frac{426+284}{2}$

$v_{avg} =$ 355 m/s

8 0

3 years ago

Wooden handles on knives do not require maintenance. TRUE FALSE

Olenka [21]

Answer: false

Explanation:

You have to make sure it doesn’t stay wet

5 0

2 years ago