Answer:
Transferred material is in the same relative position on the disk as on the original sample
Explanation:
The usefulness of blotting techniques in molecular biology is that transferred material is in the same relative position on the disk as on the original sample
Air blows from one place to another because gases move from high-pressure areas to low-pressure areas
In simple words
it happens because of pressure differences.
Answer:
r=P/C, where P is the amount of useful output ("product") produced per the amount C ("cost") of resources consumed.
Explanation:
Efficiency is often measured as the ratio of useful output to total input, which can be expressed with the mathematical formula r=P/C, where P is the amount of useful output ("product") produced per the amount C ("cost") of resources consumed.
Answer:
Yes, it is very helpful.
Explanation:
It's helpful since in a cell, plant or animal, there are a lot of different things. It's hard to memorize everything and know what they look like. Using a model can help you memorize everything better and even understand it better. If someone asked me where or what something was in a cell I think I would be able to recognize it better.
I hope this helps!
Answer:

Explanation:
From the question we are told that
The electric filed is
Generally according to Gauss law
=> 
Given that the electric field is pointing downward , the equation become

Here
is the excess charge on the surface of the earth
is the surface area of the of the earth which is mathematically represented as

Where r is the radius of the earth which has a value 
substituting values


So

Here
s the permitivity of free space with value

substituting values

