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3 years ago

Describe the parts of the wheel and axle

Physics

2 answers:

suter [353]3 years ago

8 0

Answer:

A simple machine that may be used the most often is called the wheel and axle. The wheel and axle has two basic parts: wheel and axle. It has two circular objects which includes a larger disc and a small cylinder both joined at the center.

Explanation:

Natalka [10]3 years ago

3 0

Explanation:

A simple machine that may be used the most often is called the wheel and axle. The wheel and axle has two basic parts: wheel and axle. They can be found everywhere. It has two circular objects which includes a larger disc and a small cylinder both joined at the center.The large disc is the wheel, and the small cylinder or rod is the axle. There may be two wheels attached to the axle.

There are two basic ways a wheel and axle can work together to help move things.

1. The Force is applied to the Wheel

For example, a screwdriver is an example of a wheel and axle. The handle is the wheel where the force is applied. It turns or spins and increases the force of the shaft or axle, which helps turn the screw.

Another example of force being applied to the wheel is when a doorknob is turned. The wheel (doorknob) is turned and the locking mechanism connected to the shaft turns and the door can then be opened.

2. The Force is applied to the Axle

A Ferris wheel is an example of force being applied to the axle. When the axle turns it results in the giant wheel turning. The wheel is much larger than the axle and covers more distance and area. A ceiling fan works the same way.

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A mass hanging from a spring is set in motion and its ensuing velocity is given by v (t )equals 2 pi cosine pi t for tgreater th

lianna [129]

Answer:

2(maximum), -2(minimum), -2(maximum).

Explanation:

V(t)= 2πcos πt--------------------------------------------------------------------------------(1).

Therefore, there is a need to integrate v(t) to get S(t).

S(t)= 2×sinπt + C ------------------------------------------------------------------------------(2).

Applying the condition given, we have s(0)= 0.

S(0)= 2sin ×π(0) + C.

Which means that; 0+C= 0. That is; C=0.

S(t)= 2 sin πt.

The mass moves to its highest positions at time,t=half(1/2=.5) and time,t=2.5.

Take note that; sin(π/2) = sin(5π/2) = 1 .

Also, the mass moves to its lowest position at time,t=(3/2); also, sin(3π/2) = -1.

Therefore, we have that 2 maximum; -2 minimum and -2 maximum.

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3 years ago

How was bohr atomic model similar to Rutherford's model

Juliette [100K]

Both believe that an atom contains negative charges and positive charges.
But both were different in the placement of charges

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3 years ago

Read 2 more answers

A gaseous sample of this element is bombarded by photons of various energies (in these same units). Match each photon to the res

solniwko [45]

1) n=1 -> n=2 : delta E = -5+11 = 6. The answer is D
2) n=1 -> n=3 : delta E = -2+11 = 9. The answer is B 
3) n=1 -> n=4 : delta E = -1+11 = 10. No solution available 
4) n=1 -> infinity delta E = 11. The answer is A 
5) not absorbed would be C, as there is no transition with delta E of 8.

8 0

3 years ago

you are piloting a small plane and you want to reach an airport 450 km due south in 3.0 h a wind is blowing from the west 50.0 k

alex41 [277]

Answer:

You should choose airspeed 158.11 km/h at 18.4° west of south

Explanation:

The distance to the air port is 450 km due to south

You should to reach the airport in 3 hours

→ Velocity = distance ÷ time

→ Distance = 450 km , time = 3 hours

→ The velocity of your plane = 450 ÷ 3 = 150 km/h due to south

A wind is blowing from west 50 km/h

We need to know what heading and airspeed you should choose to

reach your destination

At first we must find the resultant velocity of your plane and the wind

The south and west are perpendicular, then the resultant velocity is

→ $v_{R}=\sqrt{(v_{p})^{2}+(v_{w})^{2}}$

→ $v_{p}=150$ km/h , $v_{w}=50$ km/h

→ $v_{R}=\sqrt{(150)^{2}+(50)^{2}}=158.11$ km/h

To cancel the velocity of the wind, the pilot should maintain the velocity

of the plane at 158.11 km/h

The direction of the velocity is the angle between the resultant velocity

and the vertical (south)

→ The direction of the velocity is $tan^{-1}\frac{50}{150}=18.4$ °

The direction of the velocity is 18.4° west of south

You should choose airspeed 158.11 km/h at 18.4° west of south

8 0

3 years ago

Please help I literally don’t understand

Veseljchak [2.6K]

Answer:

A= 2

B=3

C=4

D=5

E=7

F=8

H=12

7 0

3 years ago