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kenny6666 [7]
3 years ago
7

Write a python 3 function named words_in_both that takes two strings as parameters and returns a set of only those words that ap

pear in both strings. You can assume all characters are letters or spaces. Capitalization shouldn't matter: "to", "To", "tO", and "TO" should all count as the same word. The words in the set should be all lower-case. For example, if one string contains "To", and the other string contains "TO", then the set should contain "to".
1.Use python's set intersection operator in your code.
2.Use Python's split() function, which breaks up a string into a list of strings. For example:

sentence = 'Not the comfy chair!'
print(sentence.split())
['Not', 'the', 'comfy', 'chair!']
Here's one simple example of how words_in_both() might be used:

common_words = words_in_both("She is a jack of all trades", 'Jack was tallest of all')
Computers and Technology
2 answers:
mrs_skeptik [129]3 years ago
8 0
I was going to say the same but there is no point in writing it then
s344n2d4d5 [400]3 years ago
5 0

Answer:

def words_in_both(a, b):

 a1 = set(a.lower().split())

 b1 = set(b.lower().split())

 return a1.intersection(b1)

common_words = words_in_both("She is a jack of all trades", 'Jack was tallest of all')

print(common_words)

Explanation:

Output:

{'all', 'of', 'jack'}

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eduard

Answer:

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Many people think that the main reason was the nuclear attack threat, but that was not an issue definitely. Actually this was the time of liberalization, and the power of the public universities was increased. Hence, they got the chance to share the information of various sorts with the people, and in the process internet started expanding.

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<h3>What is a report footer section?</h3>

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Answer:

Explanation:

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class Test

{

   public static void main(String[] args)

   {

       String X = "photograph";

       String Y = "tomography";

       System.out.println(X + '\n' + Y);

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       char[] word1 = X.toCharArray();

       char[] word2 = Y.toCharArray();

       

       int length1 = X.length();

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       for (int i = 0; i <= length1; i++)

       {

           for (int j = 0; j <= length2; j++)

           {

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