How are pressure and temperature related in terms of kinetic energy?
1 answer:
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Explanation:
The given data is as follows.
n = 2 mol, P = 1 atm, T = 300 K
Q = +34166 J, W= -1216 J (work done against surrounding)
=
Relation between internal energy, work and heat is as follows.
Change in internal energy () = Q + W
= [34166 + (-1216)] J
= 32950 J
Also,
=
32950 J =
1321.06 K + 300 K =
= 1621.06 K
Thus, we can conclude that the final temperature of the gas is 1621.06 K.
The free energy change(Gibbs free energy-ΔG)=-8.698 kJ/mol
<h3>Further explanation</h3>Given
Ratio of the concentrations of the products to the concentrations of the reactants is 22.3
Temperature = 37 C = 310 K
ΔG°=-16.7 kJ/mol
Required
the free energy change
Solution
Ratio of the concentration : equilbrium constant = K = 22.3
We can use Gibbs free energy :
ΔG = ΔG°+ RT ln K
R=8.314 .10⁻³ kJ/mol K