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8_murik_8 [283]
3 years ago
9

What is a good example of contact force

Physics
1 answer:
almond37 [142]3 years ago
5 0
A good example would be kicking a soccer ball, nothing will happen to the ball if you don’t directly apply force to it (through your leg)
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What is the medium when you are in your bedroom listening to the radio?
GrogVix [38]

Answer:

this equation doesn't work

Explanation:

no one listens to radio anymore

8 0
3 years ago
Read 2 more answers
A sailboat starts from rest and accelerates at a rate of 0.21 m/s^2 over a distance of 280 m. find the magnitude of the boat's f
sasho [114]

We use the kinematic equations,

v=u+at                                          (A)

S= ut + \frac{1}{2} at^2                  (B)

Here, u is initial velocity, v is final velocity, a is acceleration and t is time.

Given,  u=0, a=0.21 \ m/s^2 and s= 280 m.

Substituting these values in equation (B), we get

280 \ m = 0 +\frac{1}{2} (0.21 m/s^2) t^2 \\\\ t^2 = \frac{280 \times 2}{0.21 } \\\\ t= 51.63 \ s.

Therefore from equation (A),

v = 0 + (0.21) \times (51.63 s)= 10.84 \ m/s

Thus, the magnitude of the boat's final velocity is 10.84 m/s and the time taken by boat to travel the distance 280 m is 51.63 s



8 0
3 years ago
Mike is watching a Disney movie with his son Jason Jason likes the movie so much that he becomes excited and stands in front of
shusha [124]
You could put it in two terms.

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5 0
3 years ago
How do you find mass, volume and density? Any formulas?
Andrei [34K]
Density=mass/volume. if you know any 2 of these variables, you can figure out the missing one
5 0
3 years ago
Unpolarized light is passed through an optical filter that is oriented in the vertical direction.
VashaNatasha [74]

In order to solve this problem it is necessary to apply the concepts related to intensity and specifically described in Malus's law.

Malus's law warns that

I = I_0 cos^2\theta

Where,

\theta= Angle between the analyzer axis and the polarization axis

I_0 =Intensity of the light before passing through the polarizer

The intensity of the beam from the first polarizer is equal to the half of the initial intensity

I = \frac{I_0}{2}

Replacing with our the numerical values we get

I = \frac{46}{2}

I = 23W/m^2

Therefore the  intensity of the light that emerges from the filter is 23W/m^2

5 0
3 years ago
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