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user100 [1]
2 years ago
6

Electromagnetic waves are commonly referred to as _________

Physics
1 answer:
mart [117]2 years ago
3 0
It’s going to be both answer A and B but if you can only answer one then it’s going to be B
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At a pressure of one billionth (10–9) of atmospheric pressure, there are about 2.7 × 1010 molecules in one cubic centimeter of a
Sergeeva-Olga [200]

Answer:

Required answer =  2.7 x 10^16 MOLECULES

Explanation:

We know that

1 m = 100 cm

so 1 m^3 = (100 cm)^3 = 1000000 cm^3 = 1 x 10^6 cm3

as per question, 2.7*10^{10} molecules in 1 cm^3

so number of molecules in 1 m^3

Number of molecules = ( 2.7 x 10^10 molecules /1 cm^3 ) x ( 1 x 10^6 cm3 / 1 m3)

Number of molecules = 2.7 x 10^10 x 1 x 10^6 = 2.7 x 10^16 per m3

Required answer =  2.7 x 10^16 MOLECULES

3 0
3 years ago
In a ballistics test, a 24 g bullet traveling horizontally at 1300 m/s goes through a 25-cm-thick 360 kg stationary target and e
MaRussiya [10]

Answer:

A)0.00022s b)40363.6N c) 0.025m/s

Explanation:

Mass = 24g = 0.024kg, distance though the target = thickness of the target = 25cm = 0.25m

Initial speed of the bullet = 1300m/s, final speed = 930m/s

Using equation of motion

Distance = 1/2(vf+vi)*t (time in seconds)

t = 0.25*2/(1300+930) = 0.00022s

B) force exerted on the body

F = ma = m* (vf-vi)/t = 0.024*(930-1300)/0.00022

F = -40363N, it is negative because the body decelerated during this motion

C) using law of conservation of momentum,

M1*U1+ M2*U2(M2and U1 are the mass and initial speed of the body) = M1V1+ M2V2

The target was at rest so initial speed U2 = 0

0.024*1300 + 360*0 = 0.024*930 + 360*V2

31.2 = 22.32+360*V2

31.2-22.33 = 360*V2

V2 = 8.88/360 = 0.025m/s

8 0
3 years ago
How many meters in 2.50 miles? (Use these two conversions: 1000 m = 1 km and 1.00 km = .621 mi )
Artyom0805 [142]

2.50 miles is equal to 4026 m.

<u>Explanation:</u>

As it is known that 1000 m =1 km and 1 km = 0.621 miles. So first we have to convert miles to km and then to metre as follows.

As 1 km = 0.621 miles, then

             \text { 1 miles }=\frac{1}{0.621} \mathrm{km}

So, 2.50 miles will be equal to

            2.50 \text { miles }=\frac{2.50}{0.621} \mathrm{km}=4.026 \mathrm{km}

Then, in order to get the answer in meters, we have to convert this km to meter by the conversion of 1000 m =1 km.  So,

           1 \mathrm{km}=1000 \mathrm{m}

Thereby,

          4.026 \mathrm{km}=4026 \mathrm{m}

7 0
3 years ago
A 4 kg object moving to the left collides with and sticks to a 3 kg object moving to the right. Which of the following is true o
madam [21]

Answer:

D. The motion cannot be determined without knowing the speeds of the objects before the collision.

Explanation:

This question is tricky! We know the object moving to the left has a greater mass than the one moving to the right. We'd <em>assume</em> they would move to the left because the leftwards object has a greater mass, right?

Not. So. Fast.

We can solve for the objects' final velocity using the formula for momentum, m₁v₁ + m₂v₂ = (m₁ + m₂)v .

Now here's where the trap is sprung: <em>we don't think about the equation</em>. This shows that the final velocity of the objects and the direction depends on both the mass of the objects <em>and</em> their initial velocity.

Basically, what if the 3 kg object is moving at 1 m/s and the 4 kg object is moving at –0.5 m/s? The objects would move to the <em>right</em> after the collision!

Do we know the velocity of these objects? No, right?

That means we <em>can't</em> determine the direction of their motion <u>unless we know their initial, pre-collision velocity</u>. This question is tricky because we look at the 4 kg vs. 3 kg and automatically assume the 4 kg object would dictate the direction of motion. That's not true. It depends on velocity as well.

I hope this helps you! Have a great day!

4 0
3 years ago
A swimmer is swimming to the left with a speed of 1.0 m/s when she starts to speed up with constant acceleration. The swimmer re
kolezko [41]

Answer:

Correct answer: t = 2.86 seconds

Explanation:

We first use this formula

V² - V₀² = 2 a d    

where V is the final velocity (speed), V₀ the initial velocity (speed),

a the acceleration and d the distance.

We will calculate the acceleration from this formula

a = (V² - V₀²) / (2 d) = (2.5² - 1²) / (2 · 5) = (6.25 - 1) / 10 = 5.25 / 10

a = 0.525 m/s²

then we use this formula

V = V₀ + a t  => t = (V - V₀) / a = (2.5 - 1) / 0.525 = 1.5 / 0.525 = 2.86 seconds

t = 2.86 seconds

God is with you!!!

6 0
3 years ago
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