Electromagnetic waves are commonly referred to as _________

Physics

1 answer:

mart [117]2 years ago

3 0

It’s going to be both answer A and B but if you can only answer one then it’s going to be B

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You are riding in the passenger seat of a car as it goes around a tight turn. You slide across the seat to the passenger side do

DochEvi [55]

Answer:

1. b. The door is exerting a centripetal force on you that balances the centrifugal force of the turn.

2. b. There is no net force acting on the object.

Explanation:

1. This is because as you move to the right due to the centrifugal force of the turn, a corresponding centripetal force acts on you due to the door which does not allow you fall out of the car since, the door is exerting a centripetal force on you that balances the centrifugal force of the turn.

So, the answer is b

2. This is because, since the object moves at a constant speed and thus does not accelerate, no net force can act on it since, a net force would imply that the object accelerates. Note that a constant speed does not imply that no force acts on it. It only shows that the resultant or net force is zero since the object does not accelerate.

So, there is no net force acting on the object.

So, b is the answer.

6 0

2 years ago

As mentioned, electric fields are extremely interconnected with magnetic fields and these two types of force can travel together

Nady [450]

Answer: I think the answer is a wave/ a transverse wave, or electromagnetic waves as well.

4 0

2 years ago

Read 2 more answers

A box has a weight of 150 N and is being pulled across a horizontal floor by a force that has a magnitude of 110 N. The pulling

ivann1987 [24]

Answer:

42.99°

Explanation:

$F_h$ = Kinetic friction force

$F_{\theta}$ = Pulling force at angle $\theta$

$N_h$ = Weight of the box = 150 N

Kinetic friction force

$F_h=\muN_h$

Pulling force at angle $\theta$

$F_{\theta}=\muN_{\theta}$

N = Pulling force

According to question

$\frac{F_h}{F_{\theta}}=\frac{2}{1}\\\Rightarrow \frac{\muN_h}{\muN_{\theta}}=2\\\Rightarrow \frac{N_h}{N_{\theta}}=2\\\Rightarrow N_{\theta}=\frac{N_h}{2}\\\Rightarrow N_{\theta}=\frac{150}{2}\\\Rightarrow N_{\theta}=75\ N$