All categories

3 years ago

How can you use the properties of equality to write equivalent equations?

1 answer:

3 0

If two expressions are equal to each other, and you add the same value to both sides of the equation, the equation will remain equal. When you solve an equation, you find the value of the variable that makes the equation true. In order to solve the equation, you isolate the variable.

a = b and c ≠0, then a c = a c . Another example Consider the equation 12 = 12. Divide both sides by 4.

You might be interested in

The coordinates of the endpoint of QS are Q(-9,8) and S(9,-4). Point R is on cue as such that QR:RS Is in the ratio 1:2. What ar

marishachu [46]

R(–3, 4)

Step-by-step explanation:

Let Q(-9,8) and S(9,-4) be the given points and let R(x, y) divides QS in the ratio 1:2.

By section formula,

$R(x, y)=R\left(\frac{m x_{2}+n x_{1}}{m+n}, \frac{m y_{2}+n y_{1}}{m+n}\right)$

Here, $x_{1}=-9, y_{1}=8, \text { and } x_{2}=9, y_{2}=-4 \text { and } m=1, n=2$

Substituting this in the section formula

$R(x, y)=R\left(\frac{1(9)+2(-9)}{1+2}, \frac{1(-4)+2(8)}{1+2}\right)$

To simplifying the expression, we get

$\Rightarrow R(x, y)=R\left(\frac{9-18}{3}, \frac{-4+16}{3}\right)$

$\Rightarrow R(x, y)=R\left(\frac{-9}{3}, \frac{12}{3}\right)$

⇒ R(x,y) = R(–3,4)

Hence, the coordinates of point R is (–3, 4).

6 0

3 years ago

In Justin's school , 0.825 of the students participate a sport.if there are one thousand students in Justin's school, how many p

OLEGan [10]

825 students participate in a sport because you multiply .825 by 1,000

7 0

3 years ago

Read 2 more answers

Please help due asap

Nadusha1986 [10]

Answer:5
Explanation:Pythagorean Theorem

4 0

3 years ago

Consider a series circuit consisting of a resistor of R ohms, an inductor of L henries, and variable voltage source of V(t) volt

ser-zykov [4K]

Answer:

$I(t)=\frac{1}{3}(1-e^{-30t})$

Step-by-step explanation:

We are given that

$\frac{dI}{dt}+\frac{R}{L}I=\frac{V(t)}{L}$

R=150 ohm

L=5 H

V(t)=10 V

$P=\frac{R}{L}=\frac{150}{5}=30$

$I.F=e^{\int Pdt}=e^{\int 30 dt}=e^{30 t}$

$I(t)\times I.F=\int e^{30 t}\times 10 dt+C$

$I(t)\times e^{30 t}=\frac{10}{30}e^{30 t}+C$

$I(t)=\frac{1}{3}+Ce^{-30 t}$

I(0)=0

Substitute t=0

$0=\frac{1}{3}+C$

$C=-\frac{1}{3}$

Substitute the values

$I(t)=\frac{1}{3}-\frac{1}{3}e^{-30 t}$

$I(t)=\frac{1}{3}(1-e^{-30t})$

5 0

4 years ago

*URGENT*TEST TOMORROW*

Luden [163]

Answer:

"Dominic lived in Spain for 13 months and Columbia for 7 months."

Step-by-step explanation:

let months stayed in spain be "s" and months stayed in columbia be "c"

We can write 2 equations.

Since, lived in Spain and Columbia for a total of 20 months, we can write:

s + c = 20

Also, since 120 words per month in Spain and 150 words per month in Columbia for a total of 2610 new words, we can write:

120s + 150c=2610

Solving first for s:

s = 20 - c

Putting in 2nd and solving:

120(20 - c) + 150c = 2610

2400 - 120c + 150c = 2610

30c = 210

c = 7

Now,

s = 20 - c = 20 - 7 = 13

"Dominic lived in Spain for 13 months and Columbia for 7 months."

5 0

3 years ago

Read 2 more answers