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Vlada [557]
3 years ago
15

A gas of unknown molecular mass was allowed to effuse through a small opening under constant-pressure conditions. It required 10

5 s for 1.0 L of the gas to effuse. Under identical experimental conditions it required 30 s for 1.0 L of O2 gas to effuse.Calculate the molar mass of the unknown gas.
Chemistry
1 answer:
Shtirlitz [24]3 years ago
8 0

Answer:

The molar mass of the unknown gas is 392 g/mole

Explanation:

Firstly we write out the parameters

Volume of the gas X that effuse for 105 s = 1.0 L

Volume of the O₂ gas  that effuse for 30 s = 1.0 L

Molar mass of O₂ = 32 g/mole

Rate of effusion of the gas X = 1.0 L/105 s = 0.0095 L/s

Rate of effusion of O₂ gas = 1.0 L/30 s = 0.033 L/s

Graham's law of effusion states that

\frac{Rate A}{Rate B} = \sqrt{\frac{Molar mass B}{Molar mass A} }

Therefore we have

\frac{0.0095 L/s}{0.033 L/s}  =\sqrt{\frac{32 g/mole}{Molar mass of X} } or Molar mass of X =  \frac{32}{0.0816} g/mole = 391.99 g/mole

The molar mass of the unknown gas is 391.99 g/mole ≈ 392 g/mole

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Calcium carbonate has the chemical formula CaCO3. A certain quantity of calcium carbonate has 8.35x1025 atoms. How many moles of
kotegsom [21]

Answer

27.7 moles

Explanation:

Data Given:

Chemical formula of Calcium carbonate = CaCO₃

no. of atoms of CaCO₃ = 8.35 x 10²⁵ atoms

moles of CaCO₃= ?

Solution

First convert number of atoms to number of molecules

As

we have 5 atoms per molecule then how many molecules will be for 8.35 x 10²⁵ atoms

So, apply unity formula

               5 atoms  ≅ 1 molecule of CaCO₃

               8.35 x 10²⁵ atoms  ≅ X molecule of CaCO₃

by doing cross multiplication

      X molecule of CaCO₃ = 8.35 x 10²⁵ atoms x 1 molecule / 5 atoms

      X molecule of CaCO₃ = 1.67 x 10²⁵  molecule

Formula will be used

           no. of moles = no. of molecules / Avogadro's number . . . . (1)

Where

Avogadro's number = 6.022 x 10²³ molecules/mol

So,

Put values in equation 1

          no. of mole = 1.67 x 10²⁵/ 6.022 x 10²³ (molecules/mol)

          no. of mole = 27.7 moles

So,

moles of CaCO₃ = 27.7 moles

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the surface

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n/a

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