Answer:
The concentration of the unknown acid (HA) is 0.434M
The molar mass of HA is 13.3g/mole
Explanation:
DETERMINATION OF MOLARITY OF THE UNKNOWN ACID
CaVa/CbVb = Na/Nb
From the equation of reaction and at equivalence point, Na = Nb = 1
Therefore, CaVa = CbVb
Va (volume of acid solution) = 20mL = 20/1000 = 0.2L
Cb (concentration of KOH) = 0.715M
Vb (volume of KOH) = 12.15mL
Ca (concentration of acid) = CbVb/Va
Ca = 0.715M × 12.15mL/20mL = 0.434M
DETERMINATION OF MOLAR MASS OF HA
Number of moles of acid = concentration of acid × volume of acid solution in liters = 0.434 × 0.2 = 0.0868mole
Molar mass of HA = mass/number of moles = 1.153g/0.0868mole = 13.3g/mole
C.silver
nacl is a compound of na and cl
h2o is a compound of 2h and o
electron is a particle in an atom
N = m/M
= 200g/(12.01g/mol + 2(16.00g/mol))
=4.54mol
Given what we know, we can confirm that an example is a situation given that corroborates the information shown, while a non-example is one that does not fall in line with the information provided.
<h3>What are examples of the situations given?</h3>
- A number that is a multiple of 10 is 40, since 10 times 4 equals 40.
- In order to get a product of 10, we can multiply two and five.
- To result in a quotient of 10, we can divide one hundred by ten.
<h3>What are non-examples of the situations given?</h3>
- one non-example of a multiple of 10 would be to multiply three and seven.
- A non-example of a product of 10 is to multiply the number fifty by twenty-five.
- To result in a non-example for a quotient of 10, we can divide the number fifteen by three.
Therefore, given the definition of an example as a situation given that corroborates the information shown, while a non-example is one that does not fall in line with the information provided, we can confirm that the ones listed above are correct.
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