There are 24 valance electrons in the compound.
<h3>What are valence electrons?</h3>
We know that the valence electrons are those that are found on the valence shell of an atom. There are four atoms that can be seen in the compound that is under consideration. The atoms are selenium, bromine (2 atoms) and oxygen.
Given that there are seven valence electrons in bromine and six valence electrons in oxygen and selenium. We have;
2(7 electrons of bromine) + 6 electrons of oxygen + 4 electrons of Se
= 24 electrons
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Answer:
1.25 gram of cesium-137 will remain.
Explanation:
Given data:
Half life of cesium-137 = 30 year
Mass of cesium-137 = 5.0 g
Mass remain after 60 years = ?
Solution:
Number of half lives passed = Time elapsed / half life
Number of half lives passed = 60 year / 30 year
Number of half lives passed = 2
At time zero = 5.0 g
At first half life = 5.0 g/2 = 2.5 g
At 2nd half life = 2.5 g/ 2 = 1.25 g
Thus. 1.25 gram of cesium-137 will remain.
In order to get HgO you would need 2Hg+1O2=2HgO. Since oxygen is diatomic you need two when it stands alone causing you to need two mercuries to balance out the reactants and the product I hope this helps
289.4 F is the right one man
Answer:
The answer you would be looking for is option A because all of the other options are either false, or beneficial to us, and i took the test. Thanks
Explanation:
