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antiseptic1488 [7]
3 years ago
7

PLS HELP. WILL MARK AS THE BRAINLIEST. PLS ANSWER STEP BY STEP.

Physics
2 answers:
DedPeter [7]3 years ago
7 0
Your answer would be twelve.
Your answer is always depending on how you read your problem.
USPshnik [31]3 years ago
3 0

Answer:12

Explanation:

its the way u read it

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20. A photographer takes an average of 15 pictures per session. The total
fenix001 [56]

Answer:

A)

  • Independent variable -> number of sessions
  • Dependent variable -> number of pictures

B)

Values of the domain that make sense would be those from 0 on because there are no negative number of sessions; values of range that make sense would be also those from 0 on because there are no negative number of pictures.

C)

f(x)=15x, where "x" is the number of sessions.

If we have 22 session then:

f(22)=15*22; f(22)=f(22)=330

Explanation:

5 0
3 years ago
A sinusoidal wave is traveling along a rope. The oscillator that generates the wave completes 43.0 vibrations in 29.0 s. A given
Aliun [14]

Answer:

wavelength is 20.71 cm

Explanation:

given data

wave = 43.0 vibrations

time = 29 s

wave travels = 430 cm

time t2 = 14 s

to find out

wavelength

solution

we know here wavelength formula that is

wavelength = velocity / frequency  .........................1

here frequency = 43 / 29 = 1.4827 Hz

and velocity = 430 / 14 = 30.71 cm/s

so here from equation 1 put all value

wavelength = velocity / frequency

wavelength = 30.71 / 1.4827

wavelength = 20.71 cm

so wavelength is 20.71 cm

8 0
3 years ago
What does Charles law state?​
RoseWind [281]

Answer:

Image result for what does charles law state

The physical principle known as Charles' law states that the volume of a gas equals a constant value multiplied by its temperature as measured on the Kelvin scale (zero Kelvin corresponds to -273.15 degrees Celsius).

Explanation:

5 0
3 years ago
If you use a horizontal force of 33.0 N to slide a 11.0 kg wooden crate across a floor at a constant velocity, what is the coeff
alukav5142 [94]

Answer:

μ= 0.3

Explanation:

Given that

F= 33 N

m = 11 kg

Given that crate is moving with constant velocity is means that acceleration of the crate is zero.If acceleration of the system is zero then the total force on the system will be balance.

Therefore

F= Friction force

F= μ m g

μ=Coefficient of friction

33 = μ x 10 x 11                       ( take g= 10 m/s²)    

3 = 10 μ

μ= 0.3

Therefore coefficient of friction will be 0.3 .

3 0
3 years ago
A rocket engine uses fuel and oxidizer in a reaction that produces gas particles having a velocity of 1380 ms The desired thrust
bearhunter [10]

Answer:

a. 141.3 kg/s b. 5.49 m/s² c. i. 104228.9 N ii. 8.53 m/s² d. i. 97305.2 N ii. 9.84 m/s²

Explanation:

a. What must be the fuel/oxidizer consumption rate (in kg s1)?

The thrust T = Rv where R = mass consumption rate and v = velocity of rocket. Since T = 195000 N and v = 1380 m/s,

R = T/v = 195000 N/1380 m/s = 141.3 kg/s

b. If the initial weight of the rocket is 125000 N, what is its initial acceleration?

We also know that thrust T - W = ma since the rocket has to move against gravity. where M = mass of rocket = W/g = 125000 N/9.8m/s² = 12755.1 kg, W = weight of rocket = 125000 N, a = acceleration of rocket and T = thrust = 195000 N.

So, T - W = Ma

195000 N - 125000 N = (12755.1 kg)a

70000 N = ma

a = 70000 N/12755.1 kg = 5.49 m/s²

c. What are the weight and acceleration of the rocket at t 15.0 s after ignition?

We know that the loss in mass ΔM = mass consumption rate × time = Rt. Since R = 141.3 kg/s and t = 15 s,

ΔM = 141.3 kg/s × 15 = 2119.5 kg

The new mass is thus M = M - ΔM = 12755.1 kg - 2119.5 kg = 10635.6 kg

i.The weight after 15 seconds is thus W' = M'g = 10635.6 kg × 9.8m/s² = 104228.9 N

ii. Since T - W' = M'a. where M' is our new mass and a our new acceleration,

a = (T - W')/M'

= (195000 N - 104228.9 N)/10635.6 kg

= 90771.1 N/10635.6 kg

= 8.53 m/s²

d. What are the weight and acceleration of the rocket at 20.0 s after ignition?

We know that the loss in mass ΔM" = mass consumption rate × time = Rt. Since R = 141.3 kg/s and t = 20 s,

ΔM" = 141.3 kg/s × 20 = 2826 kg

The new mass is thus M" = M - ΔM" = 12755.1 kg - 2826 kg = 9929.1 kg

i. The weight after 20 seconds is thus W" = M"g = 9929.1 kg × 9.8m/s² = 97305.2 N

ii. Since T - W" = M"a. where M" is our new mass and a our new acceleration,

a = (T - W")/M"

= (195000 N - 97305.2 N)/9929.1 kg

= 97694.8 N/9929.1 kg

= 9.84 m/s²

4 0
3 years ago
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