Answer:
T = 0.607 seconds
Explanation:
Given:
Mass, M = 1.50 × 10⁻² kg
Radius, R = 5.50 × 10⁻² m
Now,
the time period in terms of moment of inertia is given as:
.....................1
where, T is the time period
g is the acceleration due to gravity
I is the moment of inertia
Now,
Moment of inertia, I is given as:
on substituting the moment of inertia in the equation 1, we get
or
on substituting the valeus, we get
or
T = 0.607 seconds
Hence, the time period is 0.607 seconds
Answer:
Speed, v = 312.34 m/s
Explanation:
The equation that describes a transverse wave on the string is given by :
..............(1)
Where
y = displacement of a string particle
x = position of the particle on the string
The wave is travelling in the +x direction. We have to find the speed of the wave.
The general equation of traverse wave is given by :
................(2)
On comparing equation (1) and (2) we get,
k = 3 rad/m
Since,
..............(3)
Also,
Since,
...............(4)
Speed of the wave is the product of frequency and wavelength i.e.
Using equation (3) and (4), the speed of the wave can be calculated as :
v = 312.34 m/s
Hence, the speed of the transverse wave is 312.34 m/s