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Softa [21]
3 years ago
12

A car of mass 1270 kg makes a 15.0 m radius turn at 11.8 m/s on flat ground. How much centripetal force acts on it?

Physics
1 answer:
svp [43]3 years ago
3 0

Answer:

Centripetal force = 11789 N

Explanation:

Recall that the centripetal acceleration is defined as the square of the tangential velocity divided by the radius of the circular rotation. Then for our case, the centripetal acceleration is:

ac = (11.8 m/s)^2 / 15 m = 9.28266 m/s^2

then, such acceleration on a mass of 1270 kg will render a centripetal force of:

Fc = m * ac = 1270 * 9.28266 N = 11789 N

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The mass of the sun is 1.99x10^30 kg . Jupiter is 7.79x10^8 km away from the sun and the mass of 1.90x10^27 kg
maks197457 [2]

Question is missing:

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4.16\cdot 10^{23} N

Explanation:

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where

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r is the separation between the objects

In this problem, we have

m_1 = 1.99\cdot 10^{30} kg is the mass of the sun

m_2 = 1.90\cdot 10^{27} kg is the mass of Jupiter

r=7.79\cdot 10^8 km = 7.79\cdot 10^{11} m is their separation

Solving the equation, we find

F=(6.67\cdot 10^{-11})\frac{(1.99\cdot 10^{30})(1.90\cdot 10^{27})}{(7.79\cdot 10^{11})^2}=4.16\cdot 10^{23} N

6 0
3 years ago
A ball is thrown straight up from a bridge at a speed of 11.0 m/s. If it takes 5.5 seconds to hit the water below, what is the v
seropon [69]

Answer:

 v = 42.92 m/s

Explanation:

Given,

initial speed of the ball, v = 11 m/s

time taken to hit the ground = 5.5 m/s

velocity of the ball just before it hit the ground, v = ?

time taken by the ball to reach the maximum height

using equation of motion

 v = u + at

final velocity = 0 m/s  

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time taken by the ball to reach the water from the maximum height

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 v = 42.92 m/s

Velocity of the ball just before it reaches the water is equal to v = 42.92 m/s

3 0
4 years ago
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