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DochEvi [55]
3 years ago
12

The mass % of C in methane (CH4) is?

Chemistry
2 answers:
Darina [25.2K]3 years ago
6 0

Answer:

\boxed {\boxed {\sf 74.87 \% \ C}}

Explanation:

We want to find the mass percent composition of carbon in methane: CH₄

First, we must calculate the gram formula mass, also called the molar mass. Use the values for mass found on the Periodic Table. Look for carbon and hydrogen.

  • C: 12.011 g
  • H: 1.008 g

There is no subscript after C, so there is just 1 atom. There is a subscript of 4 after H, so there are 4 atoms of hydrogen. We must multiply hydrogen's mass by 4.

  • C: 12.011 g
  • H₄: 1.008 g * 4= 4.032 g
  • CH₄= 12.011 g+ 4.032 g=16.043 g

Calculate the percent composition.

\frac {mass \ of \ part}{mass \ of \ whole} *100

The part is the carbon, or 12.011 grams.

The whole is the entire compound, CH₄, or 16.043 grams.

\frac { 12.011 \ g }{ 16.043 \ g} *100

0.748675435*100\\74.8675435

Let's round to the nearest hundredth. The 7 in the thousandth place tells us to round the 6 to a 7.

74.87 \% \ C

The mass percent of carbon is 74.87%

Andrej [43]3 years ago
3 0

Answer:

74.87% Carbon

Explanation:

The molecular mass of CH4 is 16.042 g/ mole.

X=(100 × 12.01) / 16.042= 74.87%  

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<h3>What are quantum numbers?</h3>

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The hydronium and hydroxide concentrations of a solution that is 5.0 x 10-3 M H2SO4 is 2.7.

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here ,

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The weak ionization constant (Ka)
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A weak acid is an acid that dissociates partially in the water.

The equation for the acid dissociation of carbonic acid is:

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The weak ionization constant (Ka) is the equilibrium constant for this reaction, that is, the product of the concentration of the products divided by the product of the concentrations of the reactants, all of them raised to their stoichiometric coefficients.

Ka = [H⁺] [HCO₃⁻] / [H₂CO₃]

Carbonic acid is a weak acid. Its weak ionization constant (Ka) is equal to:

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