All categories

2 years ago

Calculate the energy used by a radio of power 30W in 1 minute.

Physics

2 answers:

Paul [167]2 years ago

7 0

Answer:

1800 joule (1.8kJ)

Explanation:

Formula:

Power = Work / Time

30 = Work / 60

Work = 1800 joule

Work = 1.8kJ

Energy = Work done = 1.8kJ

Hence, Energy used is 1.8kJ.

Alekssandra [29.7K]2 years ago

5 0

Answer:

1.8kJ

Explanation:

Formula :

Energy used = Power x time

===============================================================

Given :

⇒ Power = 30 W

⇒ Time = 1 minute = 60 seconds

=============================================================

Solving :

⇒ Energy used = 30 W × 60 s

⇒ Energy used = 1,800 J

⇒ Energy used = 1.8kJ

You might be interested in

In the final stages of production, a pharmaceutical is sterilized by heating it from 25 to 75C as it moves at 0.2 m/s through a

steposvetlana [31]

Answer:

The answer is " $12682.267\ \ \frac{W}{m^2}$ "

Explanation:

Calculating the mass flow rate of fluid:

$m= \rho AV$

$= \rho \frac{\pi}{4} D^2\ V\\\\= 100 \times \frac{\pi}{4} \times (0.0127)^2\times 0.2\\\\=0.0253 \ \frac{kg}{s}\\\\$

Calculating the amount of heat transfer.

$q =m\timesC_p(T_{m,0}-T_{m,i})$

$=0.0253 \times 4000 (75-25)\\\\=0.0253 \times 4000(50)\\\\=0.0253 \times 200,000 \\\\= 5060 \ W$

Calculating the required value for heat flux:

$q"=\frac{q}{A_s}$

$=\frac{q}{\pi DL}\\\\= \frac{5060}{\pi \times 0.0127 \times 10}\\\\= 12682.267 \frac{W}{m^2}\\$

3 0

3 years ago

Any forensic scientist is equipped to study an explosion crime site.

arsen [322]

Answer:

false

Explanation:

I had the same answer for this question on my schoolwork

:) HOPE THIS HELPS

3 0

3 years ago

A 50 gram meterstick is placed on a fulcrum at its 50 cm mark. A 20 gram mass is attached at the 12 cm mark. Where should a 40 g

alekssr [168]

Answer:

The 40g mass will be attached at 69 cm

Explanation:

First, make a sketch of the meterstick with the masses placed on it;

--------------------------------------------------------------------------

↓ Δ ↓

20 g.................50 cm.................40g

38 cm y cm

Apply principle of moment;

sum of clockwise moment = sum of anticlockwise moment

40y = 20 (38)

40y = 760

y = 760 / 40

y = 19 cm

Therefore, the 40g mass will be attached at 50cm + 19cm = 69 cm

12cm 50 cm 69cm

--------------------------------------------------------------------------

↓ Δ ↓

20 g.................50 cm.................40g

38 cm 19 cm

5 0

3 years ago

The triceps muscle in the back of the upper arm extends the forearm.

iren [92.7K]

To solve this problem it is necessary to apply the concepts related to Torque as a function of Force and distance. Basically the torque is located in the forearm and would be determined by the effective perpendicular lever arm and force, that is

$\tau = F \times r$

Where,

F = Force

r = Distance

Replacing,

$\tau = 2*10^3*0.03$

$\tau = 60N\cdot m$

The moment of inertia of the boxer's forearm can be calculated from the relation between torque and moment of inertia and angular acceleration

$\tau = I \alpha$

I = Moment of inertia

$\alpha$ = Angular acceleration

Replacing with our values we have that

$I = \frac{\tau}{\alpha}$

$I = \frac{60}{120}$

$I = 0.5kg\cdot m^2$

Therefore the value of moment of inertia is $0.5kg\cdot m^2$

8 0

3 years ago

B. what does it mean to release a chemical?|

blsea [12.9K]

(A "release" of a chemical means that it is emitted to the air or water, or placed in some type of land disposal.)

3 0

3 years ago