(a) The average velocity of the car in m/s for the first leg of the run is 36.2 m/s.
(b) The average velocity (in m/s) for the total trip is 0.
<h3>
Average velocity </h3>
The average velocity of the car in m/s for the first leg of the run is calculated as follows;
Average velocity = total displacement/total time
Average velocity = (760) / (21) = 36.2 M/S
<h3>
Average velocity for total trip</h3>
The average velocity (in m/s) for the total trip is calculated as follows;
v = total displacement/total time
v = 0/(26 + 21)
v = 0
Thus, the average velocity of the car in m/s for the first leg of the run is 36.2 m/s.
The average velocity (in m/s) for the total trip is 0.
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Answer:
Explanation:
Considering Work done by friction is asked
Given
mass of block 
force 
inclination 
block is displaced by 
coefficient of kinetic friction 
Friction force 
Normal reaction 

Friction Force 
Work done by friction force

Answer:
The distance travel before stopping is 1.84 m
Explanation:
Given :
coefficient of kinetic friction 
Zak's speed 
Gravitational acceleration

Work done by frictional force is given by,




m
Therefore, the distance travel before stopping is 1.84 m
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Answer:
Correct answer: t = 2.86 seconds
Explanation:
We first use this formula
V² - V₀² = 2 a d
where V is the final velocity (speed), V₀ the initial velocity (speed),
a the acceleration and d the distance.
We will calculate the acceleration from this formula
a = (V² - V₀²) / (2 d) = (2.5² - 1²) / (2 · 5) = (6.25 - 1) / 10 = 5.25 / 10
a = 0.525 m/s²
then we use this formula
V = V₀ + a t => t = (V - V₀) / a = (2.5 - 1) / 0.525 = 1.5 / 0.525 = 2.86 seconds
t = 2.86 seconds
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