It is possible to demonstrate that the maximum distance occurs when the angle at which the projectile is fired is

.
In fact, the laws of motions on both x- and y- directions are


From the second equation, we get the time t at which the projectile hits the ground, by requiring

, and we get:

And inserting this value into Sx(t), we find

And this value is maximum when

, so this is the angle at which the projectile reaches its maximum distance.
So now we can take again the law of motion on the x-axis

And by using

, we find the value of the initial velocity v0:
Answer:
incomplete information
Explanation:
Where is diagram? no point A and point B given
Answer:
Decreases
Explanation:
The potential energy of an object is how much energy that object COULD release. When in reference to falling objects, the formula for the potential energy of an object is mgh, where m is the mass in kilograms, g is the acceleration, and h is the height. This is why, as the height of an object decreases, so does its potential energy. Hope this helps!
D is the answer hope this helped