If Aluminum has 13 protons, 14 neutrons and 13 electrons, what is its atomic mass? 26 14 27 13
2 answers:
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Answer:
The value of the magnetic field is
Explanation:
From the question we are told that
The number of turns is
The area of the loop is
The angle is
The torque is
The current is
The torque acting on the current carry loop is mathematically represented as
Where is the magnitude of the magnetic filed
Making B the subject
Substituting values
Answer:
Magnitude of electric field is 1.06 x V/m along negative X-direction
Explanation:
Given: initial velocity of proton = u = 3.5 x m/s
final velocity of proton = v = 0 m/s
initial point = 0.2 m and final point is
= 0.8 m
According to conservation of energy:
change in in kinetic energy = change in potential energy of proton
⇒
where q and m is the charge and mass of proton E is the electric field , and
is the initial and final position of proton
on substituting the respected values we get,
1.023 x = 9.6 x
x E
⇒ E = 1.06 x V/m
external force is opposite to the motion as velocity of proton decreases with distance.
Therefore, magnitude of electric field is 1.06 x V/m along negative X-direction