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Elenna [48]
3 years ago
6

PLEASE I NEED HELP ILL GIVE BRAINLYEST

Chemistry
1 answer:
Drupady [299]3 years ago
7 0

The percentage of CO2 increased 48 percent. Hope this helped!

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Four gases were combined in a gas cylinder with these partial pressures: 3.5 atm N2, 2.8 atm O2, 0.25 atm Ar, and 0.15 atm He.
Goryan [66]

Answer:

This can be solved using Dalton's Law of Partial pressures. This law states that the total pressure exerted by a gas mixture is equal to the sum of the partial pressure of each gas in the mixture as if it exist alone in a container. In order to solve, we need the partial pressures of the gases given. Calculations are as follows:

Explanation:

P = 3.00 atm + 2.80 atm + 0.25 atm + 0.15 atm

P = 6.8 atm

3.5 atm = x (6.8 atm)

x = 0.51

8 0
3 years ago
Read 2 more answers
Can matter be created or<br> destroyed?<br><br> Yes or No
anzhelika [568]

Answer:

No

Explanation:

The same amount of matter is present before and after chemical and physical changes. Matter cannot be created or destroyed

5 0
3 years ago
Read 2 more answers
a particular application calls for N2 g with a density of 1.80 g/L at 32 degrees C what must be the pressure of the n2 g in mill
baherus [9]

Answer:

1223.38 mmHg

Explanation:

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 62.3637\text{ L.mmHg }mol^{-1}K^{-1}

Also,  

Moles = mass (m) / Molar mass (M)

Density (d)  = Mass (m) / Volume (V)

So, the ideal gas equation can be written as:

PM=dRT

Given that:-

d = 1.80 g/L

Temperature = 32 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T = (32 + 273.15) K = 305.15 K

Molar mass of nitrogen gas = 28 g/mol

Applying the equation as:

P × 28 g/mol  = 1.80 g/L × 62.3637 L.mmHg/K.mol × 305.15 K

⇒P = 1223.38 mmHg

<u>1223.38 mmHg must be the pressure of the nitrogen gas.</u>

5 0
3 years ago
A very small country that has managed to stay independent of their larger neighbors. (Example: Vatican City)
Yuliya22 [10]

First option (Independent State)

6 0
3 years ago
Read 2 more answers
One of relatively few reactions that takes place directly between two solids at room temperature is In this equation, the in Ba(
yuradex [85]

Answer:

3.14 grams of ammonium thiocyanate must be used to react completely with 6.5 g barium hydroxide octahydrate.

Explanation:

Ba(OH)_2.8H_2O(s)+NH_4SCN(s)\rightarrow Ba(SCN)_2(s)+8H_2O(l)+NH_3(g)

The balance chemical equation is :

Ba(OH)_2.8H_2O(s)+2NH_4SCN(s)\rightarrow Ba(SCN)_2(s)+10H_2O(l)+2NH_3(g)

Mass of barium hydroxide octahydrate = 6.5 g

Moles of  barium hydroxide octahydrate = \frac{6.5 g}{315 g/mol}=0.020635 mol

According to reaction, 2 moles of ammonium thiocyanate reacts with1 mole of  barium hydroxide octahydrate. The 0.020635 moles of barium hydroxide octahydrate will react with:

\frac{2}{1}\times 0.020635 mol=0.04127 mol

Mass of 0.04127 moles of ammonium thiocyanate;

0.04127 mol\times 76 g/mol=3.136 g\approx 3.14 g

3.14 grams of ammonium thiocyanate must be used to react completely with 6.5 g barium hydroxide octahydrate

3 0
3 years ago
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