1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Elenna [48]
3 years ago
6

PLEASE I NEED HELP ILL GIVE BRAINLYEST

Chemistry
1 answer:
Drupady [299]3 years ago
7 0

The percentage of CO2 increased 48 percent. Hope this helped!

You might be interested in
Which equation is set up correctly to determine the volume of a 1.5 mole sample of oxygen gas at 22°C and 100 kPa?
LenKa [72]

The volume could be calculated by using  <span>V = n RT / P </span>

In which V = Volume
n = number of Moles
R= The Gas constant
T = Temperature (ideally this would be in Kelvin, but i don't see it in the option)
P = Pressure


I believe the answer is

 <span>V = (1.5mol) (0.08205 L*kPa/K*mol) (22Celsius)/100 kPa 


</span>
6 0
3 years ago
How many kj of heat are needed to completely melt 32.3 g of h2o, given that the water is at its melting point? the heat of fusio
timurjin [86]

Answer: fourth option, 10.8 kJ


Explanation:


The <em>heat of fusion</em>, also named latent heat of fusion, is the amount of heat energy required to change the state of a substance from solid to liquid (at constant pressure).


The data of the <em>heat of fusions</em> of the substances are reported in tables and they can be shown either per mole or per gram of substance.


In this case we have that the<em> heat of fusion for water </em>is reported per mole: <em>6.02 kJ/mole</em>.


The formula to calculate <em>how many kJ of heat (total heat) are needed to completely melt 32.3 g of water, given that the water is at its melting point</em> is:

  • Heat = number of moles × heat of fusion

The calculations are:

  • number of moles = mass / molar mass

        number of moles = 32.3 g / 18.015 g/mol = 1.79 mol

       

  • Heat = 1.79 mol × 6.02 kJ / mol = 10.8 kJ ← answer
5 0
3 years ago
Read 2 more answers
A single atom of an element has 21 neutrons, 20 electrons, and 20 protons. Which element is it?
sukhopar [10]

Answer:

ca

Explanation:

3 0
3 years ago
What is the most soluble salt of the following set? What is the most soluble salt of the following set?
DiKsa [7]

Answer:

(c) AgCN\ (K_{sp} =6.0\times 10^{-17})

Explanation:

The solubility product of a solid is the amount of solid dissociates into its respective ions in the solution. Thus more the value of the Ksp, the more is the salt soluble in the solvent.

So,  Given that:-

Sn(OH)_2\ (K_{sp} =1.6\times 10^{-19})

Al(OH)_3\ (K_{sp} =1.9\times 10^{-33})

AgCN\ (K_{sp} =6.0\times 10^{-17})

Fe(OH)_3\ (K_{sp} =2.6\times 10^{-39})

The salt having highest value of Ksp is AgCN. So, it is most soluble.

4 0
3 years ago
What does a net ionic equation show about a reaction
AVprozaik [17]

Answer:

A net ionic equation shows only the chemical species that are involved in a reaction, while a complete ionic equation also includes the spectator ions.

Brainlist pls!

6 0
3 years ago
Other questions:
  • What is the frequency of a wave?
    5·2 answers
  • All common cations are smaller than all common anions except one of thesea. Rubidiumb. Calciumc. Magnesiumd. sodium
    8·1 answer
  • How will the number of neutrons in an atom impact its stability?
    15·1 answer
  • List all the possible quantum-jump transitions by which the excited atom could emit a photon.
    13·1 answer
  • Which formula represents a polar molecule
    11·1 answer
  • Can you get molecules to stop wiggling??
    5·1 answer
  • A student was performing a separation of a mixture of organic compounds. The final step of the process involved a filtration of
    6·1 answer
  • What is catenation ​
    9·2 answers
  • b. Sugar and salt are both white, crystalline powders that dissolve in water. If you were given an unknown sample that contained
    15·1 answer
  • What particles would you find in a nucleus of an atom
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!