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GarryVolchara [31]
3 years ago
11

Is Particle B charged or uncharged? If charged, indicate whether it is charged positively or negatively. (n = neutron, p = proto

n, e = electron) Patice B 11p​

Physics
1 answer:
diamong [38]3 years ago
7 0

Answer:

community College program and maddie d

Explanation:

work business work and maddie

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Why can’t you feel the force of attraction between you and Mars?
laila [671]
We're millions of miles away from mars
4 0
3 years ago
A slingshot can project a pebble at a speed as high as 38.0 m/s. (a) If air resistance can be ignored, how high (in m) would a p
kipiarov [429]

Answer:

73.67 m

Explanation:

If projected straight up, we can work in 1 dimension, and we can use the following kinematic equations:

y(t) = y_0 + V_0 * t + \frac{1}{2} a t^2

V(t) = V_0 + a * t,

Where y_0 its our initial height, V_0  our initial speed, a the acceleration and t the time that has passed.

For our problem, the initial height its 0 meters, our initial speed its 38.0 m/s, the acceleration its the gravitational one ( g = 9.8 m/s^2), and the time its uknown.

We can plug this values in our equations, to obtain:

y(t) =  38 \frac{m}{s} * t - \frac{1}{2} g t^2

V(t) = 38 \frac{m}{s} - g * t

note that the acceleration point downwards, hence the minus sign.

Now, in the highest point, velocity must be zero, so, we can grab our second equation, and write:

0 m = 38 \frac{m}{s} - g * t

and obtain:

t = 38 \frac{m}{s} / g

t = 38 \frac{m}{s} / 9.8 \frac{m}{s^2}

t = 3.9 s

Plugin this time on our first equation we find:

y = 38 \frac{m}{s} * 3.9 s - \frac{1}{2} 9.8 \frac{m}{s^2} (3.9 s)^2

y=73.67 m

6 0
3 years ago
A Nerf gun is shot straight up from the ground with an initial velocity of 14.0 m/s. What is the total time the projectile is in
Sergeeva-Olga [200]

The projectile has a height <em>h</em> at time <em>t</em> given by

<em>h</em> = (14.0 m/s) <em>t</em> - 1/2 <em>g t</em> ²

where <em>g</em> = 9.80 m/s² is the magnitude of the acceleration due to gravity. Solve for <em>t</em> when <em>h</em> = 0 :

0 = (14.0 m/s) <em>t</em> - 1/2 <em>g t</em> ²

0 = 1/2 <em>t</em> (28.0 m/s - <em>g t</em> )

1/2 <em>t</em> = 0   <u>or</u>   28.0 m/s - <em>g</em> <em>t</em> = 0

The first equation says <em>t</em> = 0, which refers to the moment the gun is first fired, so we ignore that solution. We're left with

28.0 m/s - <em>g t</em> = 0

<em>t</em> = (28.0 m/s) / <em>g</em>

<em>t</em> = (28.0 m/s) / (9.80 m/s²)

<em>t</em> ≈ 2.86 s

7 0
3 years ago
Using this formula Vj = V; + at, If a vehicle starts from rest
Furkat [3]

Answer:

<em>The final speed of the vehicle is 36 m/s</em>

Explanation:

<u>Uniform Acceleration</u>

When an object changes its velocity at the same rate, the acceleration is constant.

The relation between the initial and final speeds is:

v_f=v_o+a.t

Where:

vf  = Final speed

vo = Initial speed

a   = Constant acceleration

t   = Elapsed time

The vehicle starts from rest (vo=0) and accelerates at a=4.5 m/s2 for t=8 seconds. The final speed is:

v_f=0+4.5*8

v_f=36\ m/s

The final speed of the vehicle is 36 m/s

5 0
3 years ago
Suggest values of the following in degree Celsius
ollegr [7]

Answer:

freezing water is 0°C

boiling water is 100°C

refrigerator 4°C

room is 20-22°C

3 0
3 years ago
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