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sdas [7]
3 years ago
15

It takes 38.5mL of 0.753M NaOH solution to completely neutralize 155mL of a sulfuric acid. What is the concentration of the sulf

uric acid?
Chemistry
1 answer:
Ne4ueva [31]3 years ago
8 0

Answer:

The correct solution is "93.48 M".

Explanation:

According to the question,

The number of moles of NaOH will be:

= 0.753\times 38.5

= 28.99 \ mol

The number of moles of needed H_2SO_4 will be:

= \frac{1}{2}\times 28.99

=  14.49 \ mol

hence,

The concentration of H_2SO_4 solution will be:

= \frac{Number \ of \ moles}{Volume \ of \ solution}

= \frac{14.49}{0.155}

= 93.48 \ M

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If 24.1 g of sodium hydroxide react with 22.0 g of hydrochloric acid to form 35.3g
disa [49]

Answer:

10.85 g of H2O.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

NaOH + HCl —> NaCl + H2O

Next, we shall determine the mass of NaOH that reacted and the mass of H2O produced from the balanced equation.

These can be obtained as illustrated below:

Molar mass of NaOH = 23 + 16 + 1 = 40 g/mol

Mass of NaOH from the balanced equation = 1 × 40 = 40 g

Molar mass of H2O = (2×1) + 16 = 2 + 16 = 18 g/mol

Mass of H2O from the balanced equation = 1 × 18 = 18 g

Summary:

From the balanced equation above,

40 g of NaOH reacted to produce 18 g of H2O.

Finally, we shall determine the mass of water, H2O produced from the reaction as follow:

From the balanced equation above,

40 g of NaOH reacted to produce 18 g of H2O.

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