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sdas [7]
3 years ago
15

It takes 38.5mL of 0.753M NaOH solution to completely neutralize 155mL of a sulfuric acid. What is the concentration of the sulf

uric acid?
Chemistry
1 answer:
Ne4ueva [31]3 years ago
8 0

Answer:

The correct solution is "93.48 M".

Explanation:

According to the question,

The number of moles of NaOH will be:

= 0.753\times 38.5

= 28.99 \ mol

The number of moles of needed H_2SO_4 will be:

= \frac{1}{2}\times 28.99

=  14.49 \ mol

hence,

The concentration of H_2SO_4 solution will be:

= \frac{Number \ of \ moles}{Volume \ of \ solution}

= \frac{14.49}{0.155}

= 93.48 \ M

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