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sdas [7]
3 years ago
15

It takes 38.5mL of 0.753M NaOH solution to completely neutralize 155mL of a sulfuric acid. What is the concentration of the sulf

uric acid?
Chemistry
1 answer:
Ne4ueva [31]3 years ago
8 0

Answer:

The correct solution is "93.48 M".

Explanation:

According to the question,

The number of moles of NaOH will be:

= 0.753\times 38.5

= 28.99 \ mol

The number of moles of needed H_2SO_4 will be:

= \frac{1}{2}\times 28.99

=  14.49 \ mol

hence,

The concentration of H_2SO_4 solution will be:

= \frac{Number \ of \ moles}{Volume \ of \ solution}

= \frac{14.49}{0.155}

= 93.48 \ M

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Whether or not the process is observed in nature, which of the following could account for the transformation of gallium-67 to z
Sonja [21]

Answer:

Option a: positron emission.

Explanation:

In the transformation we have:

⁶⁷Ga  →  ⁶⁷Zn  

The reaction is:

^{67}_{Z}X \rightarrow ^{67}_{Z -1}Y

For Ga to become Zn, the atom nucleus has to lose a proton, so in the given options, the reaction that involves the transformation of a proton is the option a, positron emission.

In a positron emission, a proton becomes into a neutron and a positron:

^{A}_{Z}X \rightarrow ^{A}_{Z-1}Y + ^{0}_{+1}e

Therefore, the correct answer is option a: positron emission.

I hope it helps you!

7 0
2 years ago
I need you help in this homework
Mrrafil [7]

Answer:

OPTION B ,COMPOUND CONTAINING AMMONIUM

4 0
3 years ago
If you had 24 moles of hydrogen gas how many moles of ammonia (NH3) would be produced?
dedylja [7]

Answer:

8

Explanation:

You are going to divide the 24 moles of H by the moles of H used in Ammonia. In this case 3

24/3=8

8 0
3 years ago
From Young's experiment, how does the frequency of light affect the number of lines observed?
Marina CMI [18]

Answer : (C) "Higher frequencies have larger spaces between lines".

Explanation:

In Young's experiment, the condition for constructive interference is given by :

dsin\theta=n\lambda.........(1)

n is order or number of lines observed

d is distance between slits

\theta is the angle between the path and the line from screen to the slits.

We also know that, c=\nu \lambda

or

\lambda=\dfrac{c}{\nu}

where,

c is the speed of light

\nu is frequency

\lambda is wavelength

So, equation (1) turns into

dsin\theta=n\dfrac{c}{\nu}

\nu=\dfrac{n\ c}{d\ sin\theta}

So,

\nu\propto n

or

Higher frequencies have larger spaces between line.

So, correct option is (C).

3 0
2 years ago
Read 2 more answers
You find the user guide for your DVD player. Which is the best section to start looking for information about a problem? glossar
melomori [17]
Troubleshooting is the correct answer I believe

5 0
3 years ago
Read 2 more answers
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