Question

It takes 38.5mL of 0.753M NaOH solution to completely neutralize 155mL of a sulfuric acid. What is the concentration of the sulfuric acid?

Answer 1

Answer:

The correct solution is "93.48 M".

Explanation:

According to the question,

The number of moles of NaOH will be:

= $0.753\times 38.5$

= $28.99 \ mol$

The number of moles of needed $H_2SO_4$ will be:

= $\frac{1}{2}\times 28.99$

=  $14.49 \ mol$

hence,

The concentration of $H_2SO_4$ solution will be:

= $\frac{Number \ of \ moles}{Volume \ of \ solution}$

= $\frac{14.49}{0.155}$

= $93.48 \ M$