I’m pretty sure it’s median because that’s what you would usually use for outliers.
A OK this was hard very hard
The correct option would be C
If we expand bx to jx and kx we have:
5y^2-2y-7
5y^2-7y+5y-7 then factor...
y(5y-7)+1(5y-7)
(y+1)(5y-7)
So the other factor is:
(y+1)
