Answer: bet 13x-36+(-1+3a)x2
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a4x-ax2
I believe the solution is
−9 = = 7.1
The sequence an = -5 + (n - 1)14 is an arithmetic sequence
The value of a10 is 121
<h3>How to determine the the a10-th term?</h3>
The sequence is given as:
an = -5 + (n - 1)14
To calculate the value of a10, we set n = 10
So, we have:
a10 = -5 + (10 - 1) * 14
Evaluate the difference
a10 = -5 + 9 * 14
Evaluate the product
a10 = -5 + 126
Evaluate the sum
a10 = 121
Hence, the value of a10 is 121
Read more about sequence at:
brainly.com/question/6561461
Regarding the functions in this problem, it is found that:
a) The verbal description of the inverse is: Take the third root, subtract by 5 and divide by 3.
b) The formulas are:
c) The compositions result in x, hence they are inverses.
<h3>How to obtain the inverse function?</h3>
The original function is described as follows:
- Take the third power: (3x + 5)³.
Hence the function is:
y = (3x + 5)³.
To obtain the inverse functions, we exchange x and y and then isolate y, hence:
x = (3y + 5)³
![\sqrt[3]{x} = \sqrt[3]{(3y+5)^3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D%20%3D%20%5Csqrt%5B3%5D%7B%283y%2B5%29%5E3%7D)
![3y + 5 = \sqrt[3]{x}](https://tex.z-dn.net/?f=3y%20%2B%205%20%3D%20%5Csqrt%5B3%5D%7Bx%7D)
![3y = \sqrt[3]{x} - 5](https://tex.z-dn.net/?f=3y%20%3D%20%5Csqrt%5B3%5D%7Bx%7D%20-%205)
![y = \frac{\sqrt[3]{x} - 5}{3}](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7B%5Csqrt%5B3%5D%7Bx%7D%20-%205%7D%7B3%7D)
![f^{-1}(x) = \frac{\sqrt[3]{x} - 5}{3}](https://tex.z-dn.net/?f=f%5E%7B-1%7D%28x%29%20%3D%20%5Cfrac%7B%5Csqrt%5B3%5D%7Bx%7D%20-%205%7D%7B3%7D)
The verbal description of the inverse is:
- Take the third root. sqrt[3](x).
- Subtract by 5: sqrt[3](x) - 5.
The compositions are given as follows:
More can be learned about inverse functions at brainly.com/question/11735394
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The LATEX symbol for the closed
surface integral (∯) is \oiint.
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