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ehidna [41]
3 years ago
7

Gloria’s family built a new deck using building materials made from recycled plastic bottles. As they were heated, the plastics

softened and were formed into new shapes. These plastics were ______________ solids, and their particles are arranged ________________ . These solids are different from __________________solids, which melt at a specific temperature. *
5 points
1. crystalline, vibrating, amorphous
2. amorphous, in no regular pattern, crystalline
3. amorphous, in a regular pattern, crystalline
2. crystalline, in no regular pattern, viscosity
Chemistry
1 answer:
steposvetlana [31]3 years ago
6 0

Answer:2

Explanation:

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Rusting Out. How Acids Affect the Rate of corrosion
AlekseyPX
Acids change the rate Corrosion and increase its temperature. 
8 0
3 years ago
• 1) The pressure of a sample of gas in a 2.00-L container is 876 mmHg.
kifflom [539]

Answer:

4380 mmHg

Explanation:

Boyle's Law can be used to explain the relationship between pressure and volume of an ideal gas. The pressure is inversely related to volume, so if volume decrease the pressure will increase. It can be expressed in the equation as:

P1V1=P2V2

In this question, the first condition is 2L volume and 876 mmHg pressure. Then the system changed into the second condition where the volume is 400ml and the pressure is unknown. The pressure will be:

P1V1= P2V2

876 mmHg * 2L = P2 * 400ml /(1000ml/L)

P2= 876 mmHg * 2L / 0.4L

P2= 4380 mmHg

5 0
3 years ago
what is the correct conversion factor by which to multiply to convert moles of nitrogen to moles of ammonium nitrate (NH4NO3)
Ostrovityanka [42]

Answer:

0.5

Explanation:

1 mole of ammonium nitrate contains 2 moles of nirogen

1 mole of nitrogen converts to 0.5  moles of ammonium nitrate

the conversation factor is 0.5

6 0
3 years ago
Read 2 more answers
Suppose 0.981 g of iron (II) iodide is dissolved in 150. mL of a 35.0 m M aqueous solution of silver nitrate. Calculate the fina
yaroslaw [1]

Answer:

Final molarity of iodide ion C(I-) = 0.0143M

Explanation:

n = (m(FeI(2)))/(M(FeI(2))

Molar mass of FeI(3) = 55.85+(127 x 2) = 309.85g/mol

So n = 0.981/309.85 = 0.0031 mol

V(solution) = 150mL = 0.15L

C(AgNO3) = 35mM = 0.035M = 0.035m/L

n(AgNO3) = C(AgNO3) x V(solution)

= 0.035 x 0.15 = 0.00525 mol

(AgNO3) + FeI(3) = AgI(3) + FeNO3

So, n(FeI(3)) excess = 0.00525 - 0.0031 = 0.00215mol

C(I-) = C(FeI(3)) = [n(FeI(3)) excess]/ [V(solution)] = 0.00215/0.15 = 0.0143mol/L or 0.0143M

8 0
3 years ago
How many grams of sodium sulfide can be produced when 45.3 g Na react with 105 g S?
RoseWind [281]
The chemical reaction would be as follows:

<span>2Na + S → Na2S

We are given the amount of the reactants to be used in the reaction. We use these to calculate the amount of product. We do as follows:

45.3 g Na ( 1 mol / 22.99 g ) = 1.97 mol Na
105 g S ( 1 mol / 32.06 g ) = 3.28 mol S

The limiting reactant would be Na. We calculate as follows:

1.97 mol Na ( 1 mol Na2S / 2 mol Na ) (78.04 g / mol ) = 76.87 g Na2S produced</span>
8 0
2 years ago
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