The question is incomplete, the complete question is;
The student collects the H2(g) produced by the reaction and measures its volume over water at 298 K after carefully equalizing the water levels inside and outside the gas-collection tube, as shown in the diagram below. The volume is measured to be 45.6mL . The atmospheric pressure in the lab is measured as 765 torr , and the equilibrium vapor pressure of water at 298 K is 24 torr .(i) The pressure inside the tube due to the H2(g)
Answer:
741 torr
Explanation:
From the question we can see that the atmospheric pressure in the lab is 765 torr.
The vapour pressure of water = 24 torr
From Dalton's law of partial pressure, we know that;
Total pressure = Pressure of the H2 + Partial pressure of water vapour
Therefore;
Pressure of H2 = Total pressure - Partial pressure of water vapour
Pressure of H2 = 765 torr - 24 torr = 741 torr
Answer:
Her acceleration was 0.8 m/s².
Explanation:
Given data:
Final speed v₂ = 5.4 m/s
Initial speed v₁= 3.0 m/s
Initial time t₁ = 2 s
Final time t₂ = 5 s
Acceleration = ?
Solution:
acceleration = (v₂- v₁) / (t₂ - t₁)
acceleration = 5.4 - 3 / 5-2
acceleration = 2.4 / 3 = 0.8 m/s²
I need a little more context but I believe you are correct
Atoms are electrically neutral because they have equal numbers of protons positively charged and electrons negatively charged.if an atom gains or loses one or more electrons it becomes an ion
Atomic mass of boron = 10.81
<h3>What are Isotopes?</h3>
Isotopes are variants of a particular element in which they have the same number of protons but differ in the number of neutrons in the atom.
So, here as we said we have isotopes which weigh 10.01 and 11.01.
Given,
relative abundance of B-10 = 10.1 amu
relative abundance of B- 11 = 11.01 amu
percentage of B-10 = 20%
percentage of B-11 = 80%
Then the relative atomic mass depends upon the relative abundance of various isotopes of that particular element. Suppose an element consists of two isotopes and average atomic mass is equal to
(Relativeabundance(1)×Atomicmass(1)+Relativeabundance(2)×Atomicmass(2)) / (Relativeabundance(1)+Relativeabundance(2))
Atomic mass of boron = (20 × 10.01 + 80 × 11.01) / (80 + 20 )
= 1081/100
= 10.81
To learn more about atomic mass from the given link
brainly.com/question/3187640
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