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Ahat [919]
2 years ago
7

4. Juan tiene un cilindro de 40 libras herméticamente cerrado con gas propano y lo conecta mediante una válvula a otro cilindro

de 100 libras completamente vacío. Si Juan abre la válvula del cilindro de 40 dejando pasar el gas al de 100. responda
¿Qué cantidad de gas propano le haría falta al cilindro de 100 y por qué?
Chemistry
1 answer:
ch4aika [34]2 years ago
5 0

Answer:

Ver explicacion

Explanation:

Cuando el cilindro de 40 libras está conectado al cilindro de 100 libras, generamos una presión que continúa hasta que los dos cilindros alcanzan la misma presión de gas en equilibrio. Recuerde que el cilindro de 100 libras estaba inicialmente vacío. Esto significa que su presión inicial es 0. El cilindro de 40 libras ya estaba lleno, por lo que dividimos esta cantidad en dos para tener en cuenta su distribución entre los dos cilindros.

Ahora tenemos 20 libras de gas propano presentes en cada cilindro. La implicación de esto es que, en el cilindro de 100 libras, necesitamos 80 libras adicionales para completar las 100 libras.

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The combination of potassium-sparing diuretics and salt substitutes can result in dangerously high blood levels of:
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Answer:

b. potassium.  

Explanation:

Potassium-sparing diuretics and salt substitutes are diuretics that eliminate salt and water but save potassium. They act by inhibiting the conducting sodium channels in the collecting tubule, such as amiloride and triamterene, or by blocking aldosterone, such as spironolactone.

Concomitant use of potassium-sparing diuretics together with salt substitutes may result in dangerously high blood levels of serum potassium. For this reason, it is important to consult a physician before taking these substances at the same time to avoid potential problems with potassium accumulation.

4 0
3 years ago
Based upon the information provided in the class, which of the following bond types is the strongest? Question options:
Zigmanuir [339]

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Therefore, The right choice is (B)

7 0
3 years ago
You may expect
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3 years ago
Determine the empirical formula of an oxide of silicon from the following: mass of crucible= 18.20g, mass of crucible +silicon =
lyudmila [28]
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4 0
2 years ago
Part 1: A cylinder containing 20.0 L of compressed nitrogen is connected to an empty (evacuated) vessel with an unknown volume.
baherus [9]

Answer:

The volume of the vessel is 250 L

Partial pressure of hydrogen = 189 torr

Explanation:

Using Boyle's law  

{P_1}\times {V_1}={P_2}\times {V_2}

Given ,  

V₁ = 20.0 L

V₂ = ?

P₁ = 25 atm

P₂ = 2 atm

Using above equation as:

{P_1}\times {V_1}={P_2}\times {V_2}

{25}\times {20.0}={2}\times {V_2}

{V_2}=\frac {{25}\times {20.0}}{2}\ L

{V_2}=250\ L

<u>The volume of the vessel is 250 L.</u>

According to Dalton's law of partial pressure:-

P_{H_2}=Mole\ fraction\times Total\ Pressure

So, according to definition of mole fraction:

Mole\ fraction\ of\ H_2=\frac {n_{H_2}}{n_{H_2}+n_{He}}

Also,

Mole fraction of H₂ = 1 - Mole fraction of He = 1 - 0.75 = 0.25

So,

Total pressure = 756 torr

Thus,

P_{H_2}=0.25\times 756\ torr

<u>Partial pressure of hydrogen = 189 torr.</u>

7 0
3 years ago
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