Answer:
The acceleration of the car is 7.85 m/s²
Explanation:
Given;
vx(t)= (0.910m/s³)t², given time traveled by the car 't' = 5.0 s
⇒To determine the velocity for 5 seconds, we substitute in 5.0 s for t
vx(5)= (0.910m/s³)(5s)²
= (0.910m/s³)(25s²)
vx = 22.75 m/s
⇒To determine the acceleration of the car when vx=12.0m/s
Acceleration is change in velocity per unit time
when vx=12.0m/s, our new equation becomes; 12 = (0.910m/s³)t²
Solving for t: t² = 12/0.91
t² = 13.187
t = √13.187 = 3.63 s
Acceleration = Δv/Δt
Acceleration = 7.85 m/s²
Answer:
176.58Watts
Explanation:
Power= work done /time
Where mass(m)=60kg
Height (h) =3m
Time(s)=10s
Force of gravity = 9.81m/s^2
Power=mgh/t
Power= (60kg) * (9.81m/s^2) * (3m)/10s
Power= 176.58Watts
Answer: A Answers. Assuming that the terminal velocity doesn't change during the fall, then the kinetic energy would remain constant. However the terminal velocity decreases during the fall since the air becomes denser at lower altitudes.
Explanation:
What happens to the KE of an object when it slows down and heats up? - Quora. The kinetic energy goes down and the loss of the kinetic energy is through the production of heat energy. In real world this is due to friction, or an opposing force that decelerates the object, or a combination of both.
E=energy=5.09x10^5J = 509KJ
<span>M=mass=2250g=2.25Kg </span>
<span>C=specific heat capacity of water= 4.18KJ/Kg </span>
<span>ΔT= change in temp= ? </span>
<span>E=mcΔT </span>
<span>509=(2.25)x(4.18)xΔT </span>
<span>509=9.405ΔT </span>
<span>ΔT=509/9.405=54.1degrees </span>
<span>Initial temp = 100-54 = 46 degrees </span>
<span>Hope this helps :)</span>