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BlackZzzverrR [31]
3 years ago
14

Plzz answer this question correctly

Physics
1 answer:
zvonat [6]3 years ago
4 0

Answer:

B

Explanation:

F= m×a

450N = 1.5kg × a

450/1.5 = a

a=300m/s²

IM NOT SURE THO

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A ____________ is a machine which contains a lever and a wedge that combine to make work easier.
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Answer: Simple machine

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3 years ago
A 11.0 kg satellite has a circular orbit with a period of 1.80 h and a radius of 7.50 × 106 m around a planet of unknown mass. I
Anuta_ua [19.1K]

Answer:

Explanation:

Expression for times period of a satellite can be given as follows

Time period T = 1.8 x 60 x 60

= 6480

T² = \frac{4\times \pi^2\times r^3}{GM} where T is time period , r is radius of orbit , G is gravitational constant and M is mass of the satellite.

6480² = 4 x 3.14² x 7.5³ x 10¹⁸ / GM

GM = 4 x 3.14² x 7.5³ x 10¹⁸ / 6480²

= 3.96 X 10¹⁴

Expression for acceleration due to gravity

g = GM / R² where R is radius of satellite

20 = 3.96 X 10¹⁴ / R²

R² = 3.96 X 10¹⁴ / 20

= 1.98 x 10¹³ m

R= 4.45 x 10⁶ m

8 0
3 years ago
Two similar sized stones one heavy and one light dropped from the same height into a pond explain why the impact of the heavy st
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In energy point of view, the larger stone had more potential energy before dropping. impacting the water, the larger one, having more kinetic energy which changed from potential energy, tranfered energy to the water and formed wave. the amplitude of the wave indicate the energy of the wave. more energy more amplitude.
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Which type of cloud is often taken to be a sign of fair weather?.
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The cumulus cloud.......
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2 years ago
A parallel plate capacitor filled with air with plate area 2-cm2 and plate separation of 0.5 mm is connected to a 12 V batter an
pashok25 [27]

Answer:

a) The charge of the capacitor is 4.25x10⁻¹¹C

b) The charge of the capacitor is 4.25x10⁻¹¹C because the battery is disconnected.

c) The potential difference across the plates is 18 V

d) The work is 7.64x10⁻¹⁰J

Explanation:

The capacitance of the capacitor is equal to:

C=\frac{e_{0}A }{d}

A = 2 cm² = 0.0002 m²

d = 0.5 mm = 0.0005 m

Replacing:

C=\frac{8.85x10^{-12}*0.0002 }{0.0005} =3.54x10^{-12} F = 3.54pF

a) The charge of the capacitor is equal to:

Q = C*V = 3.54 * 12 = 42.48 pC = 4.25x10⁻¹¹C

b) The charge is the same because the battery is disconnected (Q = 4.25x10⁻¹¹C)

c) If distance is increased, we have:

C=\frac{8.85x10^{-12}*0.0002 }{0.00075} =2.36x10^{-12} F=2.36pF

The potential is:

V=\frac{Q}{C} =\frac{42.48}{2.36} =18V

d) The work done is equal to:

W=VQ=18*42.48=764.6pJ=7.64x10^{-10} J

3 0
3 years ago
Read 2 more answers
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