Answer:
A. 0.5 mole of Ca(OH)₂.
B. 4.37 moles of H₂O.
Explanation:
The balanced equation for the reaction is given below:
CaC₂ + 2H₂O —> C₂H₂ + Ca(OH)₂
Next, we shall determine the mass of CaC₂ that reacted and the mass of C₂H₂ produced from the balanced equation. This can be obtained as follow:
Molar mass of CaC₂ = 40 + (12×2)
= 40 + 24
= 64 g/mol
Mass of CaC₂ from the balanced equation = 1 × 64 = 64 g
Molar mass of C₂H₂ = (12×2) + (2×1)
= 24 + 2
= 26 g/mol
Mass of C₂H₂ from the balanced equation = 1 × 26 = 26 g
SUMMARY:
From the balanced equation above,
64 g of CaC₂ reacted with 2 moles of H₂O to produce 26 g of C₂H₂ and 1 mole of Ca(OH)₂.
A. Determination of the number of mole of Ca(OH)₂ produced by the reaction of 32.0 g of CaC₂.
From the balanced equation above,
64 g of CaC₂ reacted to produce 1 mole of Ca(OH)₂.
Therefore, 32 g of CaC₂ will react to produce = (32 × 1)/64 = 0.5 mole of Ca(OH)₂.
Thus, 0.5 mole of Ca(OH)₂ were obtained from the reaction.
B. Determination of the number of mole of H₂O needed to produce 56.8 g C₂H₂.
From the balanced equation above,
2 moles of H₂O reacted to produce 26 g of C₂H₂.
Therefore, Xmol of H₂O will react to produce 56.8 g C₂H₂ i.e
Xmol of H₂O = (2 × 56.8)/26
Xmol of H₂O = 4.37 moles
Thus, 4.37 moles of H₂O is needed for the reaction.
