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marshall27 [118]
3 years ago
6

Which products would form if chlorine gas was bubbled through a solution of sodium bromide?

Chemistry
1 answer:
Ivenika [448]3 years ago
8 0
A displacement reaction will occur from the system given above. The chlorine molecules will displace the bromide ions in the solution of sodium bromide. The reaction will yield to sodium chloride and bromine. The reaction will be:

2NaBr + Cl2 = 2NaCl + Br2
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In the presence of a strong acid, litmus paper exhibits a(n) _________________ color.
tino4ka555 [31]
The answer is blue!!!!!!
3 0
3 years ago
As a chemical reaction occurs, the thermometer in the container records a drop in temperature. What is true of the reaction?
nadya68 [22]
<span>When a chemical reaction occurs and the thermometer in the container records a drop in temperature t</span>he reaction is exothermic because heat was released by the reaction.

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4 0
3 years ago
Read 2 more answers
When propane (C3H8) is burned in air (O2), it completely combusts and produces water (H2O) and carbon dioxide (CO2). How many mo
Damm [24]

Answer:

20 mol

Explanation:

First, balance the chemical reaction

C3H8 + 5O2 --> 4H2O + 3CO2

Using the mole ratio, we can multiply the moles of propane by 4 to find the moles of H2O.

5 × 4= 20

20 mol

6 0
3 years ago
Sulfur and oxygen react to produce sulfur trioxide. In a particular experiment, 7.9 grams of SO3 are produced by the reaction of
shutvik [7]

Answer:

  • <u>79%</u>

Explanation:

<u>1) Balanced chemical equation:</u>

  • 2S + 3O₂ → 2SO₃

<u>2) Mole ratio:</u>

  • 2 mol S : 3 mol O₂ : 2 mol SO₃

<u>3) Limiting reactant:</u>

  • Number of moles of O₂

        n = 6.0 g / 32.0 g/mol = 0.1875 mol O₂

  • Number of moles of S:

         n = 7.0 g / 32.065 g/mol = 0.2183 mol S

  • Ratios:

        Actual ratio: 0.1875 mol O₂ / 0.2183 mol S =0.859

        Theoretical ratio: 3 mol O₂ / 2 mol S = 1.5

Since there is a smaller proportion of O₂ (0.859) than the theoretical ratio (1.5), O₂ will be used before all S be consumed, and O₂ is the limiting reactant.

<u>4) Calcuate theoretical yield (using the limiting reactant):</u>

  • 0.1875 mol O₂ / x = 3 mol O₂ / 2 mol SO₃

  • x = 0.1875 × 2 / 3 mol SO₃ =  0.125 mol SO₃

<u>5) Yield in grams:</u>

  • mass = number of moles × molar mass = 0.125 mol × 80.06 g/mol =  10.0 g

<u>6) </u><em><u>Percent yield:</u></em>

  • Percent yield, % = (actual yield / theoretical yield) × 100
  • % = (7.9 g / 10.0 g) × 100 = 79%
6 0
4 years ago
Which of the following is NOT a good technique for managing used oil? A) Have specific, labeled catch pans available for technic
slava [35]

The answer is: B) Spills in your shop and any releases on pavement or outside should be poured down a drain.

Pouring used oil down a drain can cause damege to environment.

Oil is nonpolar substance and does not dissolve in the water (polar molecule), used oil remain existent in the drain and sewer or in the environment.

Small spills create a cumulative effect with  significant impact on the  environment.

Untended spills inside  a shop can spread to an inside  drain connected to the storm  sewer system and cause floods.

8 0
3 years ago
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