Answer:
CH3OH and NADH
Explanation:
The given chemical reaction is an redox reaction in which reduction and oxidation take place.
In the process of oxidation: electrons are loss while in the process of reduction: electrons are gained.
In the given redox reaction: CH3OH + NAD --> CH2O + NADH
NAD is reduced to NADH as NADH gains one hydrogen electron while CH3OH (methanol) is oxidized to CH2O (methanal) by losing electrons.
So, CH3OH (methanol) and NADH are the reduced forms while NAD and CH2O (methanal) are oxidized forms.
Answer:
The new concentration is 0.125 M.
Explanation:
Given data:
Initial volume V₁ = 125.0 mL
Initial molarity M₁ = 0.150 M
New volume V₂ = 25 mL +125 mL = 150 mL
New concentration M₂ = ?
Solution:
M₁V₁ = M₂V₂
0.150 M × 125 mL = M₂ × 150 mL
M₂ = 0.150 M × 125 mL / 150mL
M₂ = 18.75 M.mL/150 mL
M₂ = 0.125 M
The new concentration is 0.125 M.
Ksp of copper(II) hydroxide Cu(OH)2 is 4.9 x 10-8.
Chemical reaction (dissociation) of copper(II) hydroxide in water:
Cu(OH)2(s) → Cu²⁺(aq) + 2OH⁻(aq).
Ksp(Cu(OH)2) = [Cu²⁺]·[OH⁻]².
[Cu²⁺] = 2.42 x 10-3 mol/l; solubility od copper ions
[OH⁻] = 2[Cu²⁺] = 2 x 2.42 x 10-3 mol/l
[OH⁻] = 4.48 x 10-3 mol/l; solubility of hydroxide ions
Ksp = 2.42 x 10-3 mol/l x (4.48 x 10-3 mol/l)²
Ksp = 4.9 x 10-8
Ksp is the solubility product constant for a solid substance dissolving in an aqueous solution.
Solubility of the compound depends on the temperature of the solution and the structure of that compound.
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C. <span>High temperatures make the gas molecules move more quickly.
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