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3 years ago

PLEASE HELP MEEE I WILL MARK BRAINLIST FOR THIS ITS SUPER SIMPLE....BUT U MUST TYPE EVERYTHING

Chemistry

1 answer:

frozen [14]3 years ago

6 0

POPULATION SIZE DECREASE

Population size can increase, but it can also decrease.

We know that amount of resources available affects the population size.

Natural disasters such as floods,fires,volcanic eruptions, can also affect the population size.

Sometimes the population size will decrease so much that it threatens the entire species.

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4. Explain error and how it can impact your results from an experiment

Jet001 [13]

Random errors will shift each measurement from its true value by a random amount and in a random direction. These will affect reliability (since they're random) but may not affect the overall accuracy of a result.

3 0

3 years ago

A sample of a gas is kept at constant pressure while

Ahat [919]

Explanation:

here's the answer to your question

5 0

3 years ago

How many electrons are in the n = 2 shell of a magnesium atom?

Montano1993 [528]

Answer:

eight

Explanation:

That means there are 12 electrons in a magnesium atom

hope this helps

8 0

3 years ago

Pressure gauge at the top of a vertical oil well registers 140 bars. The oil well is 6000 m deep and filled with natural gas dow

andreyandreev [35.5K]

Explanation:

(a) The given data is as follows.

Pressure on top ( $P_{o}$ ) = 140 bar = $1.4 \times 10^{7} Pa$ (as 1 bar = $10^{5}$ )

Temperature = $15^{o}C$ = (15 + 273) K = 288 K

Density of gas = $\frac{PM}{ZRT}$

$\frac{dP}{dZ} = \rho \times g$

$\frac{dP}{dZ} = \int \frac{PM}{ZRT}$

$\int_{P_{o}}^{P_{1}} \frac{dP}{dZ} = \frac{Mg}{ZRT} \int_{0}^{4700} dZ$

$ln (\frac{P_{1}}{P_{o}}) = \frac{18.9 \times 10^{-3} \times 9.81 \times 4700 m}{0.80 \times 8.314 J/mol K \times 288 K}$

= 0.4548

$P_{1} = P_{o} \times e^{0.4548}$

= $1.4 \times 10^{7} Pa \times 1.5797$

= $2.206 \times 10^{7} Pa$

Hence, pressure at the natural gas-oil interface is $2.206 \times 10^{7} Pa$ .

(b) At the bottom of the tank,

$P_{2} = P_{1} + \rho \times g \times h$

= 2.206 \times 10^{7} Pa + 700 \times 9.81 \times (6000 - 4700)[/tex]

= $309.8 \times 10^{5} Pa$

= 309.8 bar

Hence, at the bottom of the well at $15^{o}C$ pressure is 309.8 bar.

6 0

4 years ago

Imagine an alternate universe where the value of the Planck constant is 6.6207 x 10^-36 J*s.

hoa [83]

Answer:

See explanation

Explanation:

According to Louis de Broglie, particles could exhibit wavelike properties and have an associated wavelength.

Now for a turtle with a mass of 450. g, 29. cm long, moving at 2.7 cm/s, recall that we can only describe a by quantum mechanics when the body is very small and its associated wavelength is large.

This object has a large mass, hence it is discussed by classical rather than quantum mechanics

4 0

3 years ago