The solution would be like
this for this specific problem:
<span>5.5 g = g + v^2/r </span><span>
<span>4.5 g =
v^2/r </span>
<span>v^2 = 4.5
g * r </span>
<span>v = sqrt
( 4.5 *9.81m/s^2 * 350 m) </span>
v = 124
m/s</span>
So the pilot will black out for this dive at 124
m/s. I am hoping that these answers have satisfied your query and it
will be able to help you in your endeavors, and if you would like, feel free to
ask another question.
Answer:
θ = 1.591 10⁻² rad
Explanation:
For this exercise we must suppose a criterion when two light sources are considered separated, we use the most common criterion the Rayleigh criterion that establishes that two light sources are separated census the central maximum of one of them coincides with the first minimum of the other source
Let's write the diffraction equation for a slit
a sin θ = m λ
The first minimum occurs for m = 1, also field in these we experience the angles are very small, we can approximate the sin θ = θ
θ = λ / a
In our case, the pupil is circular, so the system must be solved in polar coordinates, so a numerical constant is introduced.
θ = 1.22 λ / D
Where D is the diameter of the pupil
Let's apply this equation to our case
θ = 1.22 600 10⁻⁹ / 0.460 10⁻²
θ = 1.591 10⁻² rad
This is the angle separation to solve the two light sources
Answer:
Follows are the solution to this question:
Explanation:
In point a:
Place of particles






In point b:
when 
the Particle velocity
In point c:
Calculating the Particle acceleration:

Answer:
Freeze Fracture replication
Explanation:
<u>Freeze Fracture replication</u> is a technique that allows investigation of the microheterogeneity of a membrane so that one can see localized differences in different parts of the membrane.
Freeze fracture replication is a technique used with electron microscopy to splits frozen cell membranes apart for visualization of the membrane structure and the organization of proteins within the sea of phospholipids.
The four steps in making a freeze-fracture replication are
(i) rapid freezing,
(ii) fracturing,
(iii) replication and
(iv) replica cleaning.
Answer:
All molecules of one substance are identical (exactly the same)(2)