Answer:
Qa/Qb = k/2×2k = 1/4
Explanation:
a situation is series and b situation is parallel.
let conductance of each plate = k
so net conductance in series = k/2
net conductance in parallel = 2k
so Qa/Qb = k/2×2k = 1/4
We know, W = k. q₁q₂/ [1/r₁² - r₂² ]
Here, r₁ = R
r₂ = ∞
Substitute their values,
W = k. q₁q₂/ [1/R - 1/∞]
W = k. q₁q₂/ [1/R]
W = k. q₁q₂/ R
Hope this helps!
(a) The reactance of the inductor is 25.46 ohms.
(b) The expression for the current through the inductor is I(t) = (6.32 A) sin(134t)
<h3>Ractance of the inductor</h3>
The reactance of the inductor is calculated as follows;
XL = ωL
where;
- ω is angular frequency
- L is 190 mH
v(t) = (161 V) sin(134t)
v(t) = V sin(ωt)
The reactance of the inductor is calculated as follows;
XL = (134) x (190 x 10⁻³)
XL = 25.46 ohms
<h3>Peak current in the circuit</h3>
I₀ = V₀/XL
I₀ = (161) / (25.46)
I₀ = 6.32 A
<h3>Expression for the current through the inductor</h3>
I(t) = (6.32 A) sin(134t)
Learn more about inductance here: brainly.com/question/16765199
Answer:
The frequency heard by the motorist is 4313.2 Hz.
Explanation:
let f1 be the frequency emited by the police car and f2 be the frequency heard by the motorist, let v1 be the speed of the police car and v2 be the speed of the motorist and v = 343 m/s be the speed of sound.
because the police car is moving towards the motorist at a higher speed, then the motorist will hear a increasing frequency and according to Dopper effect, that frequency is given by:
f1 = [(v + v2/(v - v1))]×(f2)
= [( 343 + 30)/(343 - 36)]×(3550)
= 4313.2 Hz
Therefore, the frequency heard by the motorist is 4313.2 Hz.
