Answer: for ideal situation
T2 = 16.5158K
Work = - 11.4J
For appropriate generalization correlation
T2 = 308.57K
Work = 177.797MJ
Explanation:detailed calculation and explanation is shown in the image below.
Answer:
80.16 m/s^2
at t=2 s
x=42.3 m
y=16 m
z=14 m
Explanation:
solution
The x,y,z components of the velocity are donated by the i,j,k vectors.

acceleration is a derivative of velocity with respect to time.
![a_{x}=\frac{d}{dt} v_{x}=\frac{d}{dt}[16t^{2}]=32t\\a_{y}=\frac{d}{dt} v_{y}=\frac{d}{dt}[4t^{3}]=12t^{2} \\a_{z}=\frac{d}{dt} v_{z}=\frac{d}{dt}[5t+2]=5](https://tex.z-dn.net/?f=a_%7Bx%7D%3D%5Cfrac%7Bd%7D%7Bdt%7D%20v_%7Bx%7D%3D%5Cfrac%7Bd%7D%7Bdt%7D%5B16t%5E%7B2%7D%5D%3D32t%5C%5Ca_%7By%7D%3D%5Cfrac%7Bd%7D%7Bdt%7D%20v_%7By%7D%3D%5Cfrac%7Bd%7D%7Bdt%7D%5B4t%5E%7B3%7D%5D%3D12t%5E%7B2%7D%20%5C%5Ca_%7Bz%7D%3D%5Cfrac%7Bd%7D%7Bdt%7D%20v_%7Bz%7D%3D%5Cfrac%7Bd%7D%7Bdt%7D%5B5t%2B2%5D%3D5)
evaluate acceleration at 2 seconds

the magnitude of the acceleration is the square root of the sum of the square of each component of the acceleration.

position is the integral of velocity with respect to time position at a time can be found by taking by taking the definite intergral of each component.

Answer:
When the lift is greater than the weight, the aircraft gains altitude. ... Drag must be overcome for the aircraft to move, and movement is essential to obtain lift. To overcome drag and move the aircraft forward, another force is essential. This force is thrust.
Explanation:
Hope this helps!