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sveticcg [70]
2 years ago
5

Molar mass of SeOBr2 with work (PLEASE HELP ME!)

Chemistry
2 answers:
iogann1982 [59]2 years ago
8 0

Answer:

254.77 g/mol

I don't know what you mean by "with work"

Explanation:

The molar mass is the mass of a given chemical element or chemical compound (g) divided by the amount of substance (mol).

Trava [24]2 years ago
3 0

Answer:

\boxed {\boxed {\sf 254.679 \ g/mol  }}

Explanation:

The molar mass is the mass of 1 mole of particles in a substance. We can calculate using values on the Periodic Table.

First, identify the elements in the compound: SeOBr₂.

  • Selenium (Se), Oxygen (O), and Bromine (Br)

Use the Periodic Table to find the molar masses.

  • Se: 78.97 g/mol
  • O: 15.999 g/mol
  • Br: 79.90 g/mol

Notice the formula has a subscript of 2 after bromine. This means there are 2 moles of bromine in 1 mole of SeOBr₂.

To calculate the molar masses, multiply bromine's molar mass by 2, then add selenium and oxygen.

2(79.90 \ g/mol) + 15.999 \ g/mol + 78.97 \ g/mol  \\159.80 \ g/mol + 15.999 \ g/mol + 78.97 \ g/mol  \\254.679 \ g/mol

The molar mass of SeOBr₂ is <u>254.679 grams per mole</u>.

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A reaction has a standard free-energy change of -14.50 kJ mol(-3.466 kcal mol). Calculate the equilibrium constant for the react
den301095 [7]

Answer:  The equilibrium constant for the reaction at 25 °C is 346.7

Explanation:

Formula used :

\Delta G^o=-2.303\times RT\times \log K_c

where,

\Delta G^o = standard Gibb's free energy change = -14.50kJ/mol =14500 J/mol

R = universal gas constant = 8.314 J/K/mole

T = temperature = 25^0C= (25+273)K=298 K

K_c = equilibrium constant = ?

Putting in the values we get:

-14500=-2.303\times 8.314\times 298\times \log K_c

\log K_c=2.54

K_c=antilog(2.54)=346.7

The equilibrium constant for the reaction at 25 °C is 346.7

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3 years ago
What is a cause of cemical weathering? <br><br> A. sunlight<br> B. wind<br> C. gravity<br> D. acids
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Which atom is most likely to accept electrons to form an ionic bond?
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Halogens (atoms with 7 valence electrons) and Hydrogen

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Which structural feature will differ among an ester, an alcohol, and an aldehyde, regardless of which examples are being compare
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The functional group

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1) A mixture of anhydrous sodium carbonate and sodium hydrogencarbonate of mass 10.000 g was heated until it reached a constant
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The masses of the components are obtained as;

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  • Sodium carbonate =  8.708 g
<h3>What is decomposition?</h3>

The term decomposition has to do with the breakdown of the given substance into its components. The components of sodium hydrogen carbonate could be identified as water vapor, carbon dioxide gas and sodium carbonate. Among these products that have been listed here, we can see that it is only the sodium carbonate that remains as a solid. The others are gases that move away from the system that is under study.

Now putting down the equation of the reaction, we have;

2NaHCO_{3} (s) ----- > Na_{2} CO_{3} (s) + CO_{2} (g) + H_{2} O(g)

Now, the loss in  mass must be due to the carbon dioxide and the water. Hence we obtain the loss in mass to be 10.000 g -  8.708 g = 1.292 g

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