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sveticcg [70]
3 years ago
5

Molar mass of SeOBr2 with work (PLEASE HELP ME!)

Chemistry
2 answers:
iogann1982 [59]3 years ago
8 0

Answer:

254.77 g/mol

I don't know what you mean by "with work"

Explanation:

The molar mass is the mass of a given chemical element or chemical compound (g) divided by the amount of substance (mol).

Trava [24]3 years ago
3 0

Answer:

\boxed {\boxed {\sf 254.679 \ g/mol  }}

Explanation:

The molar mass is the mass of 1 mole of particles in a substance. We can calculate using values on the Periodic Table.

First, identify the elements in the compound: SeOBr₂.

  • Selenium (Se), Oxygen (O), and Bromine (Br)

Use the Periodic Table to find the molar masses.

  • Se: 78.97 g/mol
  • O: 15.999 g/mol
  • Br: 79.90 g/mol

Notice the formula has a subscript of 2 after bromine. This means there are 2 moles of bromine in 1 mole of SeOBr₂.

To calculate the molar masses, multiply bromine's molar mass by 2, then add selenium and oxygen.

2(79.90 \ g/mol) + 15.999 \ g/mol + 78.97 \ g/mol  \\159.80 \ g/mol + 15.999 \ g/mol + 78.97 \ g/mol  \\254.679 \ g/mol

The molar mass of SeOBr₂ is <u>254.679 grams per mole</u>.

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2c+02=2CO2. The moles of co2 produced when 0.25 moles of O2 react is?​
Sophie [7]
<h3>Answer:</h3>

\displaystyle 0.5 \ mol \ CO_2

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Moles
  • Compounds

<u>Stoichiometry</u>

  • Using Dimensional Analysis
  • Analyzing Reactions RxN
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced] 2C + O₂ → 2CO₂

[Given] 0.25 moles O₂

[Solve] moles CO₂

<u>Step 2: Identify Conversions</u>

[RxN] 1 mol O₂ → 2 mol CO₂

<u>Step 3: Stoichiometry</u>

  1. [DA] Set up:                                                                                                     \displaystyle 0.25 \ moles \ O_2(\frac{2 \ mol \ CO_2}{1 \ mol \ O_2})
  2. [DA] Multiply/Divide [Cancel out units]:                                                        \displaystyle 0.5 \ mol \ CO_2
7 0
3 years ago
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