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Gelneren [198K]
3 years ago
8

Which choice shows the correct sequence of features formed by continued wave erosion?

Physics
1 answer:
attashe74 [19]3 years ago
7 0

Answer:

Wave-cut cliff, sea arch, sea stacks

Explanation:

The effect of a wave erosion is made obvious by the structures formed by the wave action.

The high areas of land adjacent to the incoming wave develop the early features or the formation of wave action, which includes the <em>wave-cut cliff</em>

The continuous undercutting of the cliff by the wave results in the formation of the <em>wave cut platform</em>

The effect of the wave further on a cliff, results in the formation of a sea arch and finally a <em>sea stack</em>

Therefore, the correct sequence is the wave-cut cliff, sea arch, sea stacks

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What is the maximum value the string tension can have before the can slips? The coefficient of static friction between the can a
Naya [18.7K]

Answer:

T= 38.38 N

Explanation:

Here

mass of can = m = 3 kg

g= 9.8 m/sec2

angle θ = 40°

From figure we see the vertical and horizontal component of tension force T

If the can is to slip - then horizontal component of tension force should become equal to force of friction.

First we find force of friction

Fs= μ R

where

μ = 0.76

R = weight of can = mg = 3 × 9.8 = 29.4 N

Now horizontal component of tension

Tx= T cos 40 = T× 0.7660  N

==>T× 0.7660 = 29.4

==> T= 38.38 N

8 0
3 years ago
An electric field of 1.27 kV/m and a magnetic field of 0.490 T act on a moving electron to produce no net force. If the fields a
lesantik [10]

Answer:

v = 2591.83 m/s

Explanation:

Given that,

The electric field is 1.27 kV/m and the magnetic field is 0.49 T. We need to find the electron's speed if the fields are perpendicular to each other. The magnetic force is balanced by the electric force such that,

qE=qvB\\\\v=\dfrac{E}{B}\\\\v=\dfrac{1.27\times 10^3}{0.49}\\\\v=2591.83\ m/s

So, the speed of the electron is 2591.83 m/s.

8 0
3 years ago
A magnifier has a magnification of 8 x. How far from the lens should an object be placed so that it’s virtual image is at the ne
larisa86 [58]

The distance of the object from the lens is 3.12 cm.

<h3>What is magnification?</h3>

Magnification is the process of of enlarging an apparent size of an object.

<h3>Object distance</h3>

The object distance is calculated using the following lens formula;

M = \frac{V}{U}

where;

  • M is the magnification
  • V is the image distance
  • U is object distance

- 8 = \frac{-25}{U} \\\\U = \frac{-25}{-8} \\\\U = 3.12 \ cm

Thus, the distance of the object from the lens is 3.12 cm.

Learn more about object distance here: brainly.com/question/24894435

8 0
2 years ago
Calculate the wavelength of 26 GeV electrons. Express your answer using two significant figures. λ = m
Alenkinab [10]

Answer:

4.78 x 10^-17 m

Explanation:

E = 26 GeV

First convert GeV into J

1 GeV = 1.6 x 10^-10 J

E = 26 x 1.6 x 10^-10 = 41.6 x 10^-10 J

Use the formula for energy

E = h c / λ

Where, h is the Plank's constant and λ be the wavelength and c be the velocity of light.

λ = h c / E

λ = ( 6.63 x 10^-34 x 3 x 10^8) / (41.6 x 10^-10)

λ = 4.78 x 10^-17 m  

6 0
3 years ago
What is a healthy way to cope with distress
STALIN [3.7K]

Answer: Well there is a simple solution which is death..

5 0
3 years ago
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