Answer:
The answer to your question is below
Explanation:
a) CI Chlorine is located in group VIIA, so its must gain one electron to be stable.
b) Se Selenium is located in group VIA, it must gain 2 electrons to be stable.
c) N Nitrogen is located in group VA, it must gain 3 electrons to be stable.
d) I Iodine is located in group VIIA, so it must gain 1 electron to be stable.
e) S sulfur is located in group VIA, so it must gain 2 electrons to be stable.
The correct answer for this question is the atmosphere.
The transformation of atmospheric N2 into NH3, which is a form that plants may use, is known as biological nitrogen fixation. However, eukaryotes do not engage in the process; it is exclusive to bacteria and archaea.
It has long been recognized that some archaea can contribute to the nitrogen cycling processes (albeit some of these organisms were not initially recognized as archaea). These included both assimilatory and dissimilatory activities, such as the fixing of atmospheric nitrogen. However, rather than large terrestrial or aquatic environments, these reactions were linked to extremophilic archaea that are generally found in 'exotic' habitats like hot springs or salt-saturated lakes.
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Cd2+ + 2Hg Cd + Hg22+. Both Cd2+ + 2e Cd(s) -0.40 and Hg22+ + 2e 2Hg(l) 0.79
A chemical reaction known as an oxidation-reduction (redox) reaction includes the exchange of electrons between two substances.
Any chemical reaction in which the oxidation number of a molecule, atom, or ion changes by acquiring or losing an electron is referred to as an oxidation-reduction reaction. Decomposition Reaction is one of the several redox reactions.
This is the redox reaction's overall cell potential. Cd2+ + 2Hg Cd + Hg22+. Both Cd2+ + 2e Cd(s) -0.40 and Hg22+ + 2e 2Hg(l) 0.79
Reduction describes the increase in electrons. Oxidation and reduction always occur jointly because any loss of electrons by one substance must be followed by a gain of electrons by another.
Therefore, oxidation-reduction processes or simply redox reactions are other names for electron-transfer events.
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Answer:
Gasification refers to the conversion of coal to a mixture of gases, including carbon monoxide, hydrogen, methane, and other hydrocarbons, depending on the conditions involved.
Answer : The correct option is, (E) 7.8 atm
Explanation :
The partial pressure of
= 8.00 atm
The partial pressure of
= 5.00 atm
= 0.0025
The balanced equilibrium reaction is,

Initial pressure 8.00 5.00 0
At eqm. (8.00-x) (5.00-x) 2x
The expression of equilibrium constant
for the reaction will be:

Now put all the values in this expression, we get :

By solving the terms, we get:

The equilibrium partial pressure of
= (8.00 - x) = (8.00 - 0.15) = 7.8 atm
Therefore, the equilibrium partial pressure of
is 7.8 atm.